Can someone help please help sorry I know it’s easy but ......

ANSWER MY QUESTION OR ILL SEND BALDI AFTER YOU!!

mihalych1998 [28]

Your answers are:

b
d
a
b
c
a
c
Factor out 10 from the expression so you end up wtth 10(2k + 5)
10h + 6 - 5h + 3 --> 10h - 5h = 5h ~ 6 + 3 = 9 --> 5h + 9

6 0

3 years ago

Read 2 more answers

The Wind Mountain excavation site in New Mexico is an important archaeological location of the ancient Native American Anasazi c

timurjin [86]

Answer:

a) 28

b)

Class Limits Class Boundaries Midpoint f Rf Cf

10 - 37 9.5-37.5 23.5 7 0.096 7

38 - 65 37.5-65.5 51.5 25 0.342 32

66 - 93 65.5-93.5 79.5 26 0.356 58

94 - 121 93.5-121.5 107.5 9 0.123 67

122 - 149 121.5-149.5 135.5 5 0.068 72

150 - 177 149.5-177.5 163.5 0 0.0 72

178 - 205 177.5-20.5 191.5 1 0.014 73

Total 73 1.0

c)

The histogram is in attached file.

Step-by-step explanation:

a)

The width of class interval=range/desired number of classes

The width of class interval=(maximum-minimum)/7

The width of class interval=(200-10)/7

The width of class interval=190/7

The width of class interval=27.14=28 (rounded to next whole number)

Part(b) and part (c) is explained in attached word document.

Download docx

5 0

3 years ago

Kiera dance class starts at 4:30 pm and ends at 6:15. hiw long is her dance class

AleksAgata [21]

Her dance class is 1 hour and 45 minutes long

Hope this helps!

5 0

3 years ago

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Using the Law of Cosines, in triangle DEF, if e=18yd, d=10yd, f=22yd, find measurement of angle D

Ivahew [28]

Check the picture below.

$\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}
\\\\\\
\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}=cos(C)\implies cos^{-1}\left(\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}\right)=\measuredangle C\\\\
-------------------------------\\\\
\begin{cases}
d=10\\
e=18\\
f=22
\end{cases}\implies cos^{-1}\left(\cfrac{{{ 18}}^2+{{ 22}}^2-10^2}{2(18)(22)}\right)=\measuredangle D$

$\bf \implies cos^{-1}\left(0.893\overline{93}\right)=\measuredangle D\implies 26.63^o\approx \measuredangle D$

7 0

3 years ago

Joan needs to estimate the size of her bedroom so that she can buy enough paint to cover the walls. Two of the walls measure 2.8

labwork [276]

The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.

The measurement of two of the walls is 2.86 metres and 3.16 metre

Area of the two walls = 2(length x breadth)

Area = 2(2.86 x 3.16) = 18.0752 m²

The measurement of the other two walls is 2.86 metres and 3.42 metres

Area of the two walls = 2(length × breadth)

Area = 2(2.86 × 3.42) = 19.5624 m²

Total area = 18.0752 + 19.5624 = 37.6376 m²

If one can of paint can cover 15 m², the no. of cans required to paint the bedroom will be

No. of cans = Total area/Area covered by one can of paint

No. of cans = 37.6376/15 = 2.5091 = 3 cans (approx.)

3 0

1 year ago