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Marta_Voda [28]
3 years ago
10

An urn contains balls numbered 1 through 20. A ball is chosen, returned to the urn, and a second ball is chosen. What is the pro

bability that the first and second balls will be a 8?
Mathematics
2 answers:
stira [4]3 years ago
7 0
<h2>Answer:</h2>

The probability is:

                   \dfrac{1}{400}

<h2>Step-by-step explanation:</h2>

It is given that:

An urn contains balls numbered 1 through 20.

A ball is chosen, returned to the urn, and a second ball is chosen.

This means that this is a case of a replacement.

Hence, one of the event is independent of the other.

Now we know that the probability to get a particular number of ball is:

                  \dfrac{1}{20}

( Since, there are total 20 balls and a ball of one particular number is just unique )

i.e. \text{Probability of getting a 8}=\dfrac{1}{20}

Hence, the probability that the first and second balls will be a 8 is:

=\dfrac{1}{20}\times \dfrac{1}{20}\\\\\\=\dfrac{1}{400}

dybincka [34]3 years ago
6 0

An urn contains balls numbered 1 through 20. A ball is chosen, returned to the urn, and a second ball is chosen. The probability that the first and second balls will be a 8 is  \frac{1}{400}

<h3>Further explanation </h3>

A random variable, random quantity, aleatory variable, or stochastic variable is described as a variable that the values depend on outcomes of a random phenomenon. The formal mathematical treatment of random variables is a topic in probability theory

There are two types of random variables such as discrete and continuous. Random variables can assume only a countable number of values are called discrete. Whereas the random variables that can take on any of the countless number of values in an interval are called continuous.

The chance of the first ball being a 8 is \frac{1}{20}. Similarly, the chance of the second being a 8 is \frac{1}{20}.

To find the chance if both happening, muliply the two.  

\frac{1}{20} *   \frac{1}{20}  = \frac{1}{400}

Because since you return it  \frac{1}{20}  again and those combined make  \frac{1}{400}  since 20 * 20= 400

<h3>Learn more</h3>
  1. Learn more about urn brainly.com/question/7153497
  2. Learn more about probability  ball  brainly.com/question/3372562
  3. Learn more about probability brainly.com/question/7965468

<h3>Answer details</h3>

Grade:  9

Subject:  mathematics

Chapter:  probability

Keywords: urn,  balls, probability, second, first

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maksim [4K]

Answer:

The appropriate solution is:

(1) 22.81 minutes

(2) 0.171

Step-by-step explanation:

According to the question, the values will be:

The service rate of guess will be:

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= 8.5 \ minutes

The mean arrival rate will be:

\lambda =\frac{60}{5}

  =7.5 \ cabs/hr

The mean service rate will be:

\mu= 7.05 \ cabs/hr

(1)

The average time a cab must wait will be:

⇒ W_q=22.95-\frac{1}{7.05}

⇒       =\frac{161.798-1}{7.05}

⇒       =\frac{160.798}{7.05}

⇒       =22.81 \ minutes

(2)

The required probability will be:

⇒ P(X\geq 6)=\frac{1-2.115}{1-7.5}

⇒                  =\frac{-1.1115}{-6.5}

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6 0
2 years ago
. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte
Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

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well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}

4 0
2 years ago
Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.
fenix001 [56]

Answer:

The angle between vector \vec{u} = 5\, \vec{i} - 8\, \vec{j} and \vec{v} = 5\, \vec{i} + \, \vec{j} is approximately 1.21 radians, which is equivalent to approximately 69.3^\circ.

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

  • their dot products, and
  • the product of their lengths.

To be precise, if \theta denotes the angle between \vec{u} and \vec{v} (assume that 0^\circ \le \theta < 180^\circ or equivalently 0 \le \theta < \pi,) then:

\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}.

<h3>Dot product of the two vectors</h3>

The first component of \vec{u} is 5 and the first component of \vec{v} is also

The second component of \vec{u} is (-8) while the second component of \vec{v} is 1. The product of these two second components is (-8) \times 1= (-8).

The dot product of \vec{u} and \vec{v} will thus be:

\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}.

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both \vec{u} and \vec{v}:

  • \| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}.
  • \| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}.

<h3>Angle between the two vectors</h3>

Let \theta represent the angle between \vec{u} and \vec{v}. Apply the formula\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} to find the cosine of this angle:

\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}.

Since \theta is the angle between two vectors, its value should be between 0\; \rm radians and \pi \; \rm radians (0^\circ and 180^\circ.) That is: 0 \le \theta < \pi and 0^\circ \le \theta < 180^\circ. Apply the arccosine function (the inverse of the cosine function) to find the value of \theta:

\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ .

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iogann1982 [59]

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Nutka1998 [239]

Answer and explanation:

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