All categories

2 years ago

2(7g - 4h) - 6(5h - 3g)

Mathematics

2 answers:

pishuonlain [190]2 years ago

6 0

Answer:

32g - 38h

Step-by-step explanation:

Step 1:

14g - 8h - 30h + 18g

Step 2:

32g - 38h

Answer:

32g - 38h

Hope This Helps :)

mina [271]2 years ago

6 0

Answer:

Step-by-step explanation:

14g-8h -30h+18g

32g-38h

You might be interested in

What is the answer if the wholesale price is $68 and the markup is 85%

Brums [2.3K]

Answer: 57.8

Step-by-step explanation: you can eithere do 68 % 85 or other way which i forgot

4 0

2 years ago

Find the coordinate of point P that lies along the directed line segment from A (3, 4) to B (6, 10) and partitions the segment i

AveGali [126]

$\bf \left. \qquad \right.\textit{internal division of a line segment}
\\\\\\
A(3,4)\qquad B(6,10)\qquad
\qquad 3:2
\\\\\\
\cfrac{AP}{PB} = \cfrac{3}{2}\implies \cfrac{A}{B} = \cfrac{3}{2}\implies 2A=3B\implies 2(3,4)=3(6,10)\\\\
-------------------------------\\\\
{ P=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)}\\\\
-------------------------------$

$\bf P=\left(\cfrac{(2\cdot 3)+(3\cdot 6)}{3+2}\quad ,\quad \cfrac{(2\cdot 4)+(3\cdot 10)}{3+2}\right)
\\\\\\
P=\left( \cfrac{6+18}{5}~~,~~\cfrac{8+30}{5} \right)\implies \left( \cfrac{24}{5}~~,~~\cfrac{38}{5} \right)\implies \left( 4\frac{4}{5}~~,~~7\frac{3}{5} \right)$

8 0

2 years ago

2x2 – 5x + 67 = 0<br> What would be your first step in completing the square for the equation above?

7nadin3 [17]

Answer:

The first step is to divide all the terms by the coefficient of $x^{2}$ which is 2.

The solutions to the quadratic equation $2x^2\:-\:5x\:+\:67\:=\:0$ are:

$x=\frac{5}{4}+i\frac{\sqrt{511}}{4},\:x=\frac{5}{4}-i\frac{\sqrt{511}}{4}$

Step-by-step explanation:

Considering the equation

$2x^2\:-\:5x\:+\:67\:=\:0$

The first step is to divide all the terms by the coefficient of $x^{2}$ which is 2.

$\frac{2x^2-5x}{2}=\frac{-67}{2}$

$x^2-\frac{5x}{2}=-\frac{67}{2}$

Lets now solve the equation by completeing the remaining steps

Write equation in the form: $x^2+2ax+a^2=\left(x+a\right)^2$

Solving for $a$ ,

$2ax=-\frac{5}{2}x$

$a=-\frac{5}{4}$

$\mathrm{Add\:}a^2=\left(-\frac{5}{4}\right)^2\mathrm{\:to\:both\:sides}$

$x^2-\frac{5x}{2}+\left(-\frac{5}{4}\right)^2=-\frac{67}{2}+\left(-\frac{5}{4}\right)^2$

$x^2-\frac{5x}{2}+\left(-\frac{5}{4}\right)^2=-\frac{511}{16}$

Completing the square

$\left(x-\frac{5}{4}\right)^2=-\frac{511}{16}$

Since, you had required to know the first step in completing the square for the equation above, I hope you have got the point, but let me quickly solve the remaining solution.

For $f^2\left(x\right)=a$ the solution are $f\left(x\right)=\sqrt{a},\:-\sqrt{a}$