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3 years ago

2(7g - 4h) - 6(5h - 3g)

Mathematics

2 answers:

pishuonlain [190]3 years ago

6 0

Answer:

32g - 38h

Step-by-step explanation:

Step 1:

14g - 8h - 30h + 18g

Step 2:

32g - 38h

Answer:

32g - 38h

Hope This Helps :)

mina [271]3 years ago

6 0

Answer:

Step-by-step explanation:

14g-8h -30h+18g

32g-38h

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Please answer this question and I will give you brainliest !! Show your work !!

Diano4ka-milaya [45]

Answer:

Initiation fee:

$400

Monthly fee:

$10

Step-by-step explanation:

First, let's start by calculating the monthly fee.

Over a period of 5 months (5 -> 10 months), the member paid 50 dollars more. We can divide this number by 5 to find the monthly fee. The monthly fee is $10.

Now, we can find the initiation fee. After 5 months with the gym, the member had spent $450. As we already know, $50 is the price for 5 months, so the member paid $50 in monthly fees.

We subtract $50 from the total cost ($450) to find that the initiation fee is $400.

Now, we can write the equations for each statement.

Let m represent the monthly fee and i represent the initiation fee:

"At the end of 5 months, a member had paid a total of $450"

5m + i = 450

"At the end of 10 months, she had paid a total of $500.

You could use 2 equations for this statement:

10m + i = 500

OR, if you use the above facts to calculate the fact that there was a $50 increase from those five months, and exclude the initiation fee and the previous five months:

5m = 50

Hope this helps!

4 0

3 years ago

Find the derivative of <img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Cfrac%7B6%7D%7Bx%7D%20" id="TexFormula1" titl

aev [14]

$f'(x_0)=\lim\limits_{h\to0}\dfrac{f(x_0+h)-f(h)}{h}=\lim\limits_{x\to x_0}\dfrac{f(x)-f(x_0)}{x-x_0}\\\\f(x)=\dfrac{6}{x};\ x_0=2\\\\subtitute\\\\f'(2)=\lim\limits_{x\to2}\dfrac{\frac{6}{x}-\frac{6}{2}}{x-2}=\lim\limits_{x\to2}\dfrac{\frac{6}{x}-3}{x-2}=\lim\limits_{x\to2}\dfrac{\frac{6-3x}{x}}{x-2}=\lim\limits_{x\to 2}\dfrac{6-3x}{x(x-2)}\\\\=\lim\limits_{x\to2}\dfrac{-3(x-2)}{x(x-2)}=\lim\limits_{x\to2}\dfrac{-3}{x}=-\dfrac{3}{2}=-1.5\\\\\\An swer:\boxed{f'(2)=-1.5}$

8 0

3 years ago

F(4) =

Alex787 [66]

Function f(4) = -10 and if g(x) = 2 , x = 0.

To find f(4), we will observe the graph of f(x).

According to the graph of f(x),

when x = 4, y is -10 which means when x is 4 value of f(4) is -10.

To find the value of x when g(x) is 2, we will observe the graph of g(x).

According to the graph of g(x),

when y = 2, x is 0 which means that when x is 0, the value of g(x) is 2.

Hence, f(4) is -10 and x = 0 when g(x) = 2.

To learn more about Function here:

brainly.com/question/14418346

#SPJ1

7 0

1 year ago

Madelyn is working two summer jobs, making $20 per hour lifeguarding and making $12 per hour clearing tables. In a given week, s

Kamila [148]

Answer:

The possible values of the number of hours clearing tables are 2 , 3 , 4 , 5 hours

Step-by-step explanation:

* Lets explain how to solve the problem

- Madelyn is making $20 per hour life guarding

- She is making $12 per hour clearing tables

- She can work no more than 13 total hours

∴ The greatest time she can work is 13 hours (≤)

- She must earn no less than $180

∴ The least money she wants to earn is $180 (≥)

- If Madelyn worked 8 hours life guarding and assume that she

worked x hours clearing tables

∵ She can work no more than 13 hours

∴ 8 + x ≤ 13

- Subtract 8 from both sides

∴ x ≤ 5 ⇒ (1)

∵ She must earn no less than $180

∴ 8 × 20 + x × 12 ≥ 180

∴ 160 + 12x ≥ 180

- Subtract 60 from both sides

∴ 12x ≥ 20 ⇒ (2)

- From equation (1) ⇒ x = 1 , 2 , 3 , 4 , 5

- Substitute x in equation (2) by these values to find the right values

of x

# If x = 1

∴ 12(1) ≥ 20

- But 12 is less than 20

∴ x can not be 1

# x = 2

∴ 12(2) ≥ 20

∴ 24 ≥ 20

- 24 is greater than 20 then x can be 2

∵ 3 , 4 , 5 greater than 2

∴ All of them give answers greater than 20

∴ x can be 3 , 4, 5

∵ x represents the number of hours for clearing tables

∴ The possible values of the number of hours clearing tables are

2 , 3 , 4 , 5 hours

5 0

4 years ago

Write a polynomial function f of the least degree that has rational coefficients,

mina [271]

Answer:

$f(x)=x^4+15x^2-16$

Step-by-step explanation:

It is given that the leading coefficient of the polynomial is 1.

We need to find a polynomial function f of the least degree.

If c is a root of a polynomial then (x-c) is a factor of the polynomial.

The given zeros are -1, 1, -4i, 4i. So,

$f(x)=(x-1)(x+1)(x+4i)(x-4i)$

$f(x)=(x^2-1^2)(x^2-(4i)^2)$

$f(x)=(x^2-1)(x^2+16)$ $[\because i^2=-1]$

$f(x)=x^2(x^2+16)-1(x^2+16)$

$f(x)=x^4+16x^2-x^2-16$

$f(x)=x^4+15x^2-16$

Therefore, the required polynomial is $f(x)=x^4+15x^2-16$ .

4 0

3 years ago