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2 years ago

Please help solve 11x+10>=150

Mathematics

2 answers:

fgiga [73]2 years ago

4 0

Answer:

12.7272

Step-by-step explanation:

subtract 10 on both sides

divide by 11 on both sides 11/11>140/11

svetlana [45]2 years ago

4 0

Answer:

x=130

Step-by-step explanation:

11x+10>=150

11x>= 150-10

11x>=140

x>=140-11

x>=129

so, because "x" is bigger than 129,

so, x=130

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Calcula las siguientes potencias

Likurg_2 [28]

<span>A) -27 B) -256, x - 32 C) 1/9
</span><span>espero que esto ayude</span>

7 0

3 years ago

Is 14.875 rational or irrational

Delicious77 [7]

Answer:

not rational

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the area of the composite figure

deff fn [24]

to find the area of the figure, you first need to find the area of the separate figures: a triangle and a square.

first, find the area of the triangle:

multiply 13 and 5 to get 65.

divide 65 by 2.

32.5.

then, find the area of the rectangle:

multiply 5 and 14 to get 70.

add those answers up, and you get:

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3 0

3 years ago

Bobby wants to go on a school trip that will cost him $250. He comes up with an equation that represents how much he needs to sa

monitta

Yes, Bobby will have enough money if he saves for 9 weeks. You can find this through either substituting w for 9 in the equation, or solving the equation itself.

Substituting:

$25(9)+30$
Substitute w for 9.

$225+30$
Simplify.

$225+30=255$
Solve.

255 is greater than 250, so yes, he will have enough money saved.

Solving the equation:

$25w+30=250$
Original Equation

$25w=220$
Subtract 30 from both sides.

$w=8.8$
Divide both sides by 25.

The number of weeks he needs is 8.8. When rounding it up, you get 9.

4 0

3 years ago

Suppose a ball is thrown upward to a height of h 0 meters. After each bounce, the ball rebounds to a fraction r of its previous

gladu [14]

Answer:

A)1st term:45

2nd term:48.75

3rd term:49.6875

4th term:49.921875

B) Sₙ = h₀ + 2h₀((∞, n=1) Σrⁿ)

Step-by-step explanation:

We are given;

h₀ = Initial height of the ball = 30

r = Rebound fraction = 0.25

a) The arithmetic sequence of bouncing balls is given by the following;

Sₙ=h₀+2h₀(r¹+r²+r³+r⁴.........rⁿ)

The first term of the sequence is;

S₁ = h₀ + 2h₀r¹

S₁ = 30 + (2 × 30 × 0.25)

S₁ = 45

The second term of the sequence is;

S₂ = h₀ + 2h₀(r¹+r²)

S₂ = 30 + (2 × 30 × (0.25 + 0.25²)) = 48.75

The third term of the sequence is;

S₃ = h₀ + 2h₀(r¹ + r² + r³) = 30 + (2 × 30 × (0.25 + 0.25² + 0.25³)) = 49.6875

S₄ = h₀ + 2h₀(r¹ + r² + r³ + r⁴)

S₄ = 30 + (2 × 30 × (0.25 + 0.25² + 0.25³ + 0.25⁴)) = 49.921875

B) The general expression for the nth term of the sequence is;

Sₙ = h₀ + 2h₀((∞, n=1) Σrⁿ)

4 0

3 years ago