Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
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Answer:
B. to the right of 0
Step-by-step explanation:
the opposite of -10 would be 10 and out of all the answer choices the number 10 only fits into B.
Answer:
https://www.caverna.k12.ky.us/userfiles/110/Classes/7142//userfiles/110/my%20files/study%20guide%20answer%20key%20(1).pdf?id=4059
Step-by-step explanation:
copy and past this pdf
Answer:
x=3
Step-by-step explanation:
7x-3=18
7x=18+3
7x=21
x=3
Answer:
Step-by-step explanation:
Given
The above table
Required
Determine the probability of a sum that is a multiple of 6
Represent the event that an outcome is a multiple of 6 with M.
List out all possible values of M
Number of M is
Total possible outcome is:
The theoretical probability is then calculated as follows:
In this case, it is:
Simplify fraction
