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alexandr402 [8]
3 years ago
9

Create a list of the odd numbers between 1 and n (include 1 as well as n -- if it's odd-- in the list). Associate the list with

the variable odds.
Mathematics
1 answer:
sukhopar [10]3 years ago
7 0
The odd numbers can be generated by adding 2 to the first odd number.

Starting with 1 as the first odd number, you get 1, 3, 5, 7, 9, ...

A general formula to name the odd numbers is 2n + 1, where n can take any whole value.

Look:

n          2n + 1

0          0+1 = 1
1          2(1) + 1 = 2 + 1 = 3
2          2(2) + 1 = 4+1 = 5
3          3(2) + 1 = 6 + 1 = 7
4          4(2) + 1 = 8 + 1 = 9.

So, you now can use the general formula 2n + 1 to generate any odd number, starting with n = 0 to generate the first odd number, 1.
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Step-by-step explanation:

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A cell phone company $500 for a new phone and $60 for a monthly plan. If C(t) is a rational function that represents the average
lisov135 [29]

The range of a function is the set of possible values that can be obtained from the dependent variable. The range of the function is: R: (500, \infty)

Given that:

Phone = \$500

Monthly\ Plan = \$60

Let the number of months be t. So, the function C(t) is calculated as follows:

C(t) = Phone + Monthly\ Plan \times t

C(t) = 500 + 60 \times t

C(t) = 500 + 60t

The range is calculated as follows:

The smallest possible value of t is 0 i.e. when no monthly subscription is done.

So, we have:

C(0) = 500 + 60\times 0= 500 + 0 = 500

And the highest is \infty i.e. for a large value of t

So, we have:

C(\infty) = 500 + 60\times \infty= 500 + \infty = \infty

Hence, the range of the function is:

R: (500, \infty)

Read more about range of functions at:

brainly.com/question/13824428

5 0
3 years ago
A young couple purchases their first new home in 2011 for​ $95,000. They sell it to move into a bigger home in 2018 for​ $105,00
mart [117]

Given:

The value of home in 2011 is $95,000.

The value of home in 2018 is $105,000.

To find:

The exponential model for the value of the home.

Solution:

The general exponential model is

y=ab^x       ...(i)

where, a is initial value and b is growth factor.

Let 2011 is initial year and x be the number of years after 2011.

So, initial value of home is 95,000, i.e., a=95,000.

Put a=95000 in (i).

y=95000b^x       ...(ii)

The value of home in 2018 is $105,000. It means the value of y is 105000 at x=7.

105000=95000b^7

\dfrac{105000}{95000}=b^7

\dfrac{21}{19}=b^7

Taking 7th root on both sides, we get

\left(\dfrac{21}{19}\right)^{\frac{1}{7}}=b

Put b=\left(\dfrac{21}{19}\right)^{\frac{1}{7}} in (ii).

y=95000\left(\left(\dfrac{21}{19}\right)^{\frac{1}{7}}\right)^x

y=95000\left(\dfrac{21}{19}\right)^{\frac{x}{7}}

Therefore, the required exponential model for the value of home is y=95000\left(\dfrac{21}{19}\right)^{\frac{x}{7}}, where x is the number of years after 2011.

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3 years ago
A skier is trying to decide whether or not to buy a season ski pass. a daily pass cost $70. a season las costs $300. the skier w
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Answer:

hi, can you please answer mine too it's just a 1 question I really need the answer because I have to pass it later at 10 pm and it's already 9:01pm I hope you can help me:(

Step-by-step explanation:

about your question I'll just put it in the comment section:)

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