9514 1404 393
Answer:
the correct answer is marked
Step-by-step explanation:
When the graph of the left side of the equation does not intersect the graph of the right side of the equation, there are no solutions.
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<em>Additional comment</em>
Even if you extend the domain to complex numbers, there are no solutions. The f(x) = |x| function always returns a positive real value, even for complex numbers.
Answer:
90 Degrees.
The angle which is equal to its supplement is 90 degrees.
None of these couples are solutions, (11, 3)(11, 3); (−1, −6)(−1, −6); (−3, 3)(−3, 3); <span>(7, 0). Perhaps the choice of answer are insufficient. we can add (1, 48) the couple (7, 0) and (7, 0)(1, 48) is a true answer, why? because it verifies the equation.</span>
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get
= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],
applying L'Hospital rule again ,we get,
= > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2
For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.
Hence 2a - b =0 => 2a = b ------(A)
limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,
= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2
[0/0 form], applying L'Hospital rule again ,we get,
limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2
from (A), we have , 2a = b => 2a = -2 => a = -1
Hence a =-1 & b = -2
Answer:
7
Step-by-step explanation:
xy + (z-x)
x = 3
y = 2
z = 4
3×2 + (4-3)
6+1
= 7
