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yawa3891 [41]
3 years ago
9

A farmer divided his piece of land into 2 equivalent groups and the quality of the soil is the same in both of these groups. He

used fertilizers for the first group of land. He did not use fertilizers for the second group of land. At the end of the season, he measured the yield of the crops in these 2 groups. Is the study observational or experimental
Mathematics
1 answer:
Dimas [21]3 years ago
7 0

Answer:

  1. Observational would mean that he (farmer) has no direct impact or change on the statistical study.
  2. Experiment would mean that he imposed a certain treatment up a group in this case it would be the land.
  3. Hence we can determine that the the study was an experimental one.
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The answer to all of these problems
-BARSIC- [3]
1) area of a cicular pool
area of a circle=πr^2   d=2.5 then r=2.5/2
A=3.14 *(2.5/2)^2
A=4.906m^2 A=4.9m^2

2) arae of a coin 
<span>(if i read it right d=15mm?)
</span>A=πr^2   d=15 then r=15/2
A=3.14*(15/2)^2 =176.6mm^2


Rest all are same problems u try to solve it
4 0
3 years ago
Based on the pattern, what are the next two terms of the sequence?<br> 7, 7/4 , 7/16 , 7/64, 7/256
IrinaVladis [17]

Answer:

7/1024 and 7/4096

Step-by-step explanation:

4×4=16

4×16=64

4×64=256

4×256=1024

4×1024=4096

hope this helps!

5 0
3 years ago
2/4 plus 1/3 as a fraction
QveST [7]

Answer: 5/6

Step-by-step explanation: trust me on this

7 0
3 years ago
Read 2 more answers
The area of a rectangular piece of cardboard is represented by
Liula [17]

This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.

Area of a rectangle:

The area of rectangle of length l and width w is given by:

A = wl

w(2w + 3) = 9

From this, we get that:

l = 2w + 3, A = 9

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}

x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}

\Delta = b^{2} - 4ac

In this question:

w(2w+3) = 9

2w^2 + 3w - 9 = 0

Thus a quadratic equation with a = 2, b = 3, c = -9

Then

\Delta = 3^2 - 4(2)(-9) = 81

w_{1} = \frac{-3 + \sqrt{81}}{2*2} = 1.5

w_{2} = \frac{-3 - \sqrt{81}}{2*2} = -3

Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.

Another similar problem can be found at brainly.com/question/16995958

5 0
3 years ago
Please help me I tried to do it
anyanavicka [17]
You do 9x27=243 then take 2x31=62 add 243+62=305 then take 305 and subtract it from 28 305-28=277 
so if i did it right you should get n=277
8 0
3 years ago
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