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TiliK225 [7]
3 years ago
10

Greg has decreased his running time by 1/10 minute each of the last six weeks. Write an expression to represent the total change

in his time over the last six weeks. Then, find the total change.
Mathematics
2 answers:
Nastasia [14]3 years ago
7 0

x is your starting running time. 1/10 of a minute is 6 seconds, so you can do x - 6(6). 6 times 6 = 36, so your answer is x - 36 seconds. 36 seconds.

Zarrin [17]3 years ago
7 0

Answer:

Total change = <em>x </em>- 36 seconds.

Step-by-step explanation:

Let Greg's initial running time be <em>x </em>seconds.

Also, 1/10 minute = 6 seconds.

In the first week, his running time = <em>x </em>- 6

In the second week, his running time = <em>x </em>- 6 - 6 = <em>x </em>- 2(6)

In the third week, his running time = <em>x </em>- 6 - 6 - 6 = <em>x </em>- 3(6)

....

....

In the sixth week, his running time = <em>x </em>- 6(6) = <em>x </em>- 36

Hence, the total change = <em>x </em>- 36.

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Which of the following correctly translates "quotient"?
tatiyna

Answer:

A quotient is division.

Step-by-step explanation:

Addition is sum

Division is quotient

muultiplication is product

subtraction is difference

5 0
3 years ago
What are the solutions of 3(2m − 1) ≤ 6m − 2?
kaheart [24]

Hello from MrBillDoesMath!

Answer:

The solution set is the set all all real number m

 

Discussion:

3(2m-1) <= 6m-2       =>

3*2m - 3*1 <= 6m-2  =>

6m - 3 <.= 6m-2       =>   (Subtract 6m from both sides)

0-3 <= -2     =>

-3 < = -2      


As -3 <=-2 is always true the solution set is the set all all real number m

Regards,  

MrB


4 0
3 years ago
Using the functions f(x) = 2x + 7, g(x) = x2 - 4, and h(x) = 5x. Find all of the following. Make sure your answer is in simplest
Stolb23 [73]

Answer:

Given

f(x) = 2x+7

g(x) = x^2-4

h(x) = 5x

a. 4h(x)

= 4 * 5x

= 20x

b. f(x) - g(x)

f(x) - g(x) = 2x + 7 - (x^2 - 4)

= 2x+7-x^2+4

=-x^2+2x+7+4

=-x^2+2x+11

c. f(g(x)) = 2(g(x))+7

=2(x^2-4) +7

=2x^2-8+7

=2x^2-1

d. g(x)h(x) = (x^2-4)(5x)

= 5x^3 - 20x

e. g(x) / f(x) = x2 - 4/ 2x + 7

7 0
3 years ago
O terreno da fazenda de Eduardo foi aumentado 2 m na horizontal e 2 m na vertical. Se antes do aumento o terreno tinha o formato
Novay_Z [31]

Answer:

New area of Eduardo's farm after the increase = x² + 4x + 4

Nova área da fazenda de Eduardo após o aumento = x² + 4x + 4

Step-by-step explanation:

English Translation

The land on Eduardo's farm was increased by 2 m horizontally and 2 m vertically. If before the increase the land was shaped like an x-side square, what is the new area after the increases?

Solution

The previous area of Eduardo's farm is the are of a square with side lenght of x.

Area of a square = (side length)² = x²

Then, the land on Eduardo's farm was increased by 2 m horizontally and 2 m vertically.

New horizontal length of Eduardo's farm = (x+2)

New vertical length of Eduardo's farm = (x+2)

New area of Eduardo's farm = (x+2)(x+2)

= x² + 4x + 4

In Portugese/Em português

A área anterior da fazenda de Eduardo é a de um quadrado com comprimento lateral de x.

Área de um quadrado = (comprimento lateral)² = x²

Em seguida, o terreno da fazenda de Eduardo foi aumentado 2 m na horizontal e 2 m na vertical.

Novo comprimento horizontal da fazenda de Eduardo = (x + 2)

Novo comprimento vertical da fazenda de Eduardo = (x + 2)

Nova área da fazenda de Eduardo

= (x + 2) (x + 2) = x² + 4x + 4

Hope this Helps!!!

Espero que isto ajude!!!

7 0
4 years ago
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V125BC [204]
She will have 3 servings with some trail mix left over
3 0
3 years ago
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