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sladkih [1.3K]
3 years ago
13

Plsss help want is the second answer

Mathematics
2 answers:
aivan3 [116]3 years ago
6 0

Answer:

A)5\frac{1}{2}

Step-by-step explanation:

To multiply a number and a mixed number, first convert the improper fraction to a mixed number. This can be done by multiplying the "number" part of the mixed number by the denominator (number underneath the fraction bar) and then adding the result to the numerator. After doing so, one can either multiply the improper fraction by the number, and then simplify the result, or one can cross simplify the number and the denominator, then multiply by the numerator.

4 * 1\frac{3}{8}\\\\4 * \frac{11}{8}\\\\=\frac{44}{8}\\\\= \frac{11}{2}

Now one must convert this improper fraction to a mixed number. One can do this by diving the numerator by the denominator, writing the result as the "number" part of the mixed number, and then writing the remainder as the numerator of the fraction.

5\frac{1}{2}

docker41 [41]3 years ago
3 0

Answer:

5 1/2 is your second answer :)

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a) The tangent to y=e^{ax} at x=p has slope

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and y=e^{ap} at this point. It passes through the origin, so its equation is

y - 0 = ae^{ap} (x - 0) \implies y = ae^{ap} x

It also passes through the point (p,e^{ap}) on the curve, so

y - e^{ap} = ae^{ap} (x - p) \implies y = e^{ap} + ae^{ap} x - ape^{ap}

By substitution,

ae^{ap} x = e^{ap} + ae^{ap} x - ape^{ap} \implies e^{ap} = ape^{ap} \implies ap=1 \\\\ \implies \boxed{p=\dfrac1a}

b) The normal to y=e^{ax} at x=2p has slope

-\dfrac1{y'(2p)} = -\dfrac1{ae^{2ap}} = -1 \implies ae^{2ap} = 1

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ae^{2ap} = ae^2 = 1 \implies \boxed{a = \dfrac1{e^2} \text{ and } p = e^2}

c) The tangent line equation is then

y = \dfrac1{e^2} e^1 x \implies \boxed{y = \dfrac xe}

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Congrats

Step-by-step explanation:

What are you asking?

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