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Korolek [52]
2 years ago
11

A rectangular drawing is enlarged by 30%. The original dimensions of this drawing are 16cm x 24cm.

Mathematics
1 answer:
Phoenix [80]2 years ago
4 0

Answer:

Step-by-step explanation: Scale \frac{130}{100} = \frac{13}{10}

New dimensions 16 * 1.3 --- 24*1.3 =20.8 cm * 31.2 cm

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Find the value of x. If your answer is not an integer, express it in simplest radical form.
DedPeter [7]

Answer:

x = 8√5

Step-by-step explanation:

for right triangle

c^2 = a^2 + b^2

with c is the hypotenuse; a & b are the other sides

(4 + 16)^2 = (4√5)^2 + x^2

400 = 80 + x^2

x^2 = 320

x^2 = 64(5)

√x^2 = √64(√5)

x = 8√5

7 0
2 years ago
What is the measure of angle x?<br>Enter your answer in the box.<br>X =<br>9​
Svet_ta [14]

Answer:

X=9?

90°

Step-by-step explanation:

4 0
3 years ago
NEED HELP I need to fill in the highlighted parts
Gemiola [76]

The statements and reasons why the given statements are true are presented in the following two column proofs;

Question 1

Given: 9·(x + 6) - 41 = 75

Prove \ x = \dfrac{62}{9}

Statement                   {} Reason

S1. 9·(x + 6) - 41 = 75   {}  R1. <u>Given</u>

S2. 9·(x + 6)  =  116        {}R2. <u>Addition property</u>

S3. <u>9·x + 54 = 116 </u>         {}R3. Distributive property

S4. 9·x = 62                   {}R4. <u>Subtraction property</u>

S5. x = \dfrac{62}{9}                     {} R5. <u>Division property of equality</u>

Question 2.

Statement                                     {}        Reason

S1. m∠A + m∠B = m∠D   {}                     R1.  Given

S2. ∠C and ∠D form a Linear Pair   {}   R2. Definition of linear pair

S3. ∠C and ∠D are supplementary   {}R3. <u>Linear pair ∠s are supplementary</u>

S4. <u>∠C + ∠D = 180° </u>  {}                           R4. Definition of supplementary

S5. m∠C + m∠A + m∠B = 180°   {}         R5. <u>Substitution property</u>

Question 3.

Statement                                     {} Reason

S1. ∠BDA ≅ ∠A                             {} R1. Given

S2. ∠BDA ≅ ∠CDE                      {}  R2. <u>Vertical angle theorem</u>

S3. ∠CDE ≅ ∠A                      {}       R3. Transitive property of congruency

S4. m∠CDE = m∠A                    {}   R4. <u>Definition of congruency</u>

S5. <u>(13·x + 20)° = (14·x + 15)°</u>      {}   R5. Substitution Property of Equality

S6. 14·x° = 13·x + 5°                       {}R6. <u>Subtraction property</u>

S7. x = 5                      {}                  R7. Subtraction property

Learn more here:

brainly.com/question/11331230

6 0
3 years ago
Please help this is hard math
Rainbow [258]

Answer:

y=-4x+2

Step-by-step explanation:

  • First we find the slope of the line AB passing through the point (2,0)
  • line AB is perpendicular to the line y=\frac{1}{4}x-3 , this equation is slope intercept for, which is y=mx+b so our m or slope is \frac{1}{4}
  • Since the slope of line AB is perpendicular to m=\frac{1}{4} then we use the equation slope of line1\times slopeofline2=-1 , so what do we multiply \frac{1}{4} by to get -1? -4 right, so that's the slope of line AB with the point (2,0)
  • Now line CD is parallel to line AB, that means it has the same slope as AB, so slope of CD is -4
  • So we make the equation y-y_1=m(x-x_1) so m= -4 and our point is (-1,6)
  • y-(6)=-4(x-(-1)\\y-6=-4x-4\\y=-4x-4+6\\y=-4x+2 thats the equation of line side CD
6 0
2 years ago
Read 2 more answers
Find the slope-intercept form of the equation of the line passing through the given points.
Ugo [173]
The\ slope-intercept\ form:y=mx+b\\\\The\ slope-point\ form:y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

(1;\ 1)\to x_1=1;\ y_1=1\\\left(3;-\dfrac{1}{5}\right)\to x_2=3;\ y_2=-\dfrac{1}{5}.\\\\Subtitute:\\\\m=\dfrac{-\frac{1}{5}-1}{3-1}=\dfrac{-1\frac{1}{5}}{2}=-\dfrac{\frac{6}{5}}{2}=-\dfrac{\not6^3}{5}\cdot\dfrac{1}{\not2_1}=-\dfrac{3}{5}


y-1=-\dfrac{3}{5}\left(x-1\right)\\\\y-1=-\dfrac{3}{5}x+\dfrac{3}{5}\ \ \ \ |add\ 1\ to\ both\ sides\\\\\boxed{y=-\frac{3}{5}x+1\frac{3}{5}}


5 0
3 years ago
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