Not completely sure but i think it is 16
Answer:
1) w₁=4 - i w₂= -4 + i
2) w₁= 3 - i w₂= -3 + i
3) w₁= 1 + 2i w₂= - 1 - 2i
4) w₁= 2- 3i w₂= -2 + 3i
5) w₁= 5 - 2i w₂= -5 + 2i
6) w₁= 5 - 3i w₂= -5 + 3i
Step-by-step explanation:
The root of a complex number is given by:
![\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bz%7D%3D%5Csqrt%5Bn%5D%7Br%7D%28Cos%28%5Cfrac%7B%5Ctheta%2B2k%5Cpi%7D%7Bn%7D%29%20%2B%20i%20Sin%28%5Cfrac%7B%5Ctheta%2B2k%5Cpi%7D%7Bn%7D%29%29)
where:
r: is the module of the complex number
θ: is the angle of the complex number to the positive axis x
n: index of the root
1) z = 15 − 8i ⇒ r=17 θ= -0.4899 rad
w₁=
=4-i
w₂=
=-1+i
2) z = 8 − 6i ⇒ r=10 θ= -0.6435 rad
w₁=
= 3 - i
w₂=
= -3 + i
3) z = −3 + 4i ⇒ r=5 θ= -0.9316 rad
w₁=
= 1 + 2i
w₂=
= -1 - 2i
4) z = −5 − 12i ⇒ r=13 θ= 0.4426 rad
w₁=
= 2- 3i
w₂=
= -2 + 3i
5) z = 21 − 20i ⇒ r=29 θ= -0.8098 rad
w₁=
= 5 - 2i
w₂=
= -5 + 2i
6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad
w₁=
= 5 - 3i
w₂=
= -5 + 3i
Answer:
Distance=9.43 units
Step-by-step explanation:
When you have two coordinates and you need to find the distance between them, you can use the distance formula.
D=sqrt(7-2)^2+(3-(-5))^2
D=sqrt(5^2+8^2)
D=sqrt(25+64)
D=sqrt89
D=9.43, rounded to the nearest hundredth.
Therefore, your distance would be 9.43 units.
I hope this helped! Have a good rest of your day~
-1, because the equation for the slope is y2-y1/x2-x1. So let's bring the y value in the second set of point, which is 20, and bring the first y value in the first set of points, which is 5. 20-5 is 15. Now let's subtract the x values. So the second x from the second parentheses x value is -7, and the first x value from the first parentheses is 8. -7-8 is -15. Now we have this division equation, 15/-15, which is -1. So therefore, the slope of the line will be -1.
(4 feet wide), 12 feet in length. 4*3=12 4*12=48