Question

PLEASE HELP ME.....

Answer 1

Answer:

They would meet each other at $01 : 24$ PM.

Step-by-step explanation:

• Erik took a trip to see his friend Mike who lives 308 miles away.

• He left his place at 10 AM driving at 70 mph.

• In 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph.

As Erik left his house at 10 AM driving at 70 mph and in 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph. It means

Erik left his place at 12:00 PM noon.

so, at 12:00 PM Erik had already traveled:

                                                                      $2\times 70=140\:\:miles$

Miles left $=308-140=168\:\:miles$

Let 't' be the time when they meet

so

$70t\:+\:50t\:=168$

$120t=168$

$\mathrm{Divide\:both\:sides\:by\:}120$

$\frac{120t}{120}=\frac{168}{120}$

$t=\frac{7}{5}$

so

$t=\frac{7}{5}=1.4\:\:hours$

or $1$ hour and $24$ minutes after $12:00$ noon

i.e.

$12\:+\:1.4\:=1\:O'clock\:+\:24\:minutes$

Therefore, they would meet each other at $01 : 24$ PM.