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4 years ago

PLEASE HELP ME.....

Mathematics

1 answer:

Virty [35]4 years ago

7 0

Answer:

They would meet each other at $01 : 24$ PM.

Step-by-step explanation:

Erik took a trip to see his friend Mike who lives 308 miles away.

He left his place at 10 AM driving at 70 mph.

In 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph.

As Erik left his house at 10 AM driving at 70 mph and in 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph. It means

Erik left his place at 12:00 PM noon.

so, at 12:00 PM Erik had already traveled:

$2\times 70=140\:\:miles$

Miles left $=308-140=168\:\:miles$

Let 't' be the time when they meet

$70t\:+\:50t\:=168$

$120t=168$

$\mathrm{Divide\:both\:sides\:by\:}120$

$\frac{120t}{120}=\frac{168}{120}$

$t=\frac{7}{5}$

$t=\frac{7}{5}=1.4\:\:hours$

or $1$ hour and $24$ minutes after $12:00$ noon

i.e.

$12\:+\:1.4\:=1\:O'clock\:+\:24\:minutes$

Therefore, they would meet each other at $01 : 24$ PM.

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