Which statement is always true?
2 answers:
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If the angles of a convex octagon are then the smallest angle is 21°.
Given The exterior angles of convex octagon are
and we have to find the value of smallest angle.
The sum of the angles of a convex octagon is 360°
so to calculate the smallest angle we need to find out the value of x first and which is calculated by summing up all the exterior angles and put them equal to 360.
(2x+6)+(x+13)+(2x-1)+(2x+12)+(2x-17)+(3x-4)+(3x-10)+4x=360
2x+6+x+13+2x-1+2x+12+2x-17+3x-4+3x-10+4x=360
2x+x+2x+2x+2x+3x+3x+4x+6+13-1+12-17-4-10=360
19x-1=360
19x=360+1
19x=361
x=361/19
x=19
Putting the value of x in all the angles and we will find the following:
2x+6=2*19+6=44
x+13=19+13=32
2x-1=2*19-1=37
2x+12=2*19+12=50
2x-17=2*19-17=21
3x-4=3*19-4=51
3x-10=3*19-10=47
4x=4*19=76
Hence among all the exterior angles the smallest angle is 21°.
Learn more about angles at brainly.com/question/25716982
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For a better understanding of the explanation provided here kindly go through the file attached.
Since, the weight attached is already at the lowest point at time, t=0, therefore, the equation will have a -9 as it's "amplitude" and it will be a Cosine function. This is because in cosine function, the function has the value of the amplitude at t=0.
Now, we know that the total angle in radians covered by a cosine in a given period is and the period given in the question is t=3 seconds. Therefore, the angular velocity,
of the mentioned system will be:
Combining all the above information, we see that the equation which models the distance, d, of the weight from its equilibrium after t seconds will be:
Thus, Option B is the correct option. The attached diagram is the graph of the option B and we can see clearly that at t=3, the weight indeed returns to it's original position.
