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user100 [1]
3 years ago
6

Which table represents a function ? please help quick

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0

Answer:

The first table (the one that has -3 as the first number in the table)

Step-by-step explanation:

A table is a function when the x column doesn't have any numbers repeated.  

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Jamal draws a 180-degree straight line on his paper.He draws a line down the middle of the line perpendicular to the first line.
PolarNik [594]

Answer:

I think it will be 90 degree

4 0
4 years ago
Can someone help me, please
shepuryov [24]

Answer:

yes... 13.3

Step-by-step explanation:

4 0
4 years ago
Find the missing term in each pair of equivalent ratios <br> ____:13=48:104
Arte-miy333 [17]
You can treat ratios as fractions
x:13=48:104
x/13=48/104
simplify 48/104
48/104=24/52=12/26=6/13
x/13=6/13
multiply both sides by 13
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the missing number is 6
7 0
4 years ago
Any help? 20 Points
Greeley [361]

Answer:

  see below

Step-by-step explanation:

A cubic with a positive leading coefficient will have a general trend of upward to the right. (If the leading coefficient is negative, it will trend downward.) If there is only one real zero, it will cross the x-axis exactly once. There may or may not be two turning points, but there won't be any more than that. (There may be no turning points.)

The attached graph shows a couple of examples. The turning points and inflection points may be on either side of the x-axis.

4 0
4 years ago
The roots of a quadratic equation ax2+bx+c=0 are 3+sqrt2 and 3−sqrt2. Find the values of b and c assuming that a=1.
slamgirl [31]

Answer:

b=-6\\c=7

Step-by-step explanation:

we know that

The general equation of a quadratic function in factored form is equal to

y=a(x-x_1)(x-x_2)

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

a=1\\x_1=3+\sqrt{2}\\x_2=3-\sqrt{2}

substitute

y=(1)(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))

Applying the distributive property convert to expanded form

y=x^2-x(3-\sqrt{2})-x(3+\sqrt{2})+(3+\sqrt{2})(3-\sqrt{2})

y=x^2-(3x-x\sqrt{2})-(3x+x\sqrt{2})+(9-2)

y=x^2-3x+x\sqrt{2}-3x-x\sqrt{2}+7

y=x^2-6x+7

therefore

b=-6\\c=7

7 0
3 years ago
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