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seropon [69]
3 years ago
7

Help me pls TwT, I’m really confused

Mathematics
1 answer:
Marat540 [252]3 years ago
8 0
Okay so to not be confused it’s c I got this one for class
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The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass
ahrayia [7]
Each half-life reduces a sample by one half.
So after 1 half-life there is 1/2 left
2 half-lives 1/4
3 half-lives 1/8
4 half-lives 1/16
5 half-lives 1/32
There would be (1/32) of 120 remaining.
or 3.75 grams.

Source:
http://www.1728.org/halflife.htm


5 0
4 years ago
Please help me with this problem...It is a quick problem ​
In-s [12.5K]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the area of the Red Cross-section??? PLEASE HELP!!!!
alexandr1967 [171]
X is the radius of the slice.  So we must find the equation of the side of the cone.

y=mx+b, so now we must use two points to solve for the slope, or "m".

m=(y2-y1)/(x2-x1)

m=(0-15)/(5-0)

m=-15/5

m=-3  so our line so far is:

y=-3x+b, b=y-intercept=value of y when x=0, which we can see is 15 ft so:

y=-3x+15

Now the radius is x, so we must solve for x from the equation above...

-3x+15=y  subtract 15 from both sides

-3x=y-15  divide both sides by -3

x=(15-y)/3

And area of this circle is:

A=πx^2, and using x found above:

A=(π/9)(15-y)^2

A=(π/9)(225-30y+y^2), so when y=6 ft

A=(π/9)(225-30*6+6^2)

A=(π/9)(81)

A=9π or if we let π=pi

A=9pi ft^2
8 0
3 years ago
Can someone please help me on mymath
bekas [8.4K]
Yes, I will help. What do you need help with?
3 0
3 years ago
If the product of roots of the equation given below is 4, then find the value of m.
Vikentia [17]

Answer:

m=-2

Step-by-step explanation:

As the product of the roots of a quadratic equation is c/a in ax^2+bx+c=0

here a=2, b=+8, c=-m^3

Given c/a=4

-m^3/2=4

-m^3=8

m^3= -8

m=-2.

8 0
3 years ago
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