All categories

3 years ago

So I have a math presentation in a couple of minutes do you have any advice to boost my confidence?

Mathematics

1 answer:

Sedaia [141]3 years ago

3 0

Answer:

keep calm and believe in yourself

You might be interested in

In a group of 700 people only 5% of them have red hair how many people hade red hair

Svetradugi [14.3K]

35 people have red hair. Do 700 times 0.05.

3 0

3 years ago

By Faraday's Law, if a conducting wire of length ℓ meters moves at velocity v m/s perpendicular to a magnetic field of strength

andrew11 [14]

V = -Bρv
dV/dv = -Bρ = -8 x 0.7 = -5.6

4 0

4 years ago

Determine the value of x in the diagram

Sidana [21]

Answer:

3x + x + 3x + x = 360

8x = 360

x = 45

3(45)= 135

Step-by-step explanation:

3 0

4 years ago

Convert the percent to a decimal

Zanzabum

Answer:

40.0

18%

14.375%

1/250

6325

Step-by-step explanation:

Convert the percent to a decimal 4,000%

4000% = 4000/100 = 40.0

Convert the decimal or whole number to a percent.

0.36 * 1/2

= 0.36/2 * 100

= 0.18 * 100

= 18%

Convert the decimal or whole number to a percent.

1.15 * 1/8

= 1.15/8 * 100

= 14.375%

Convert the percent to a reduced fraction, mixed number, or whole number.

0.4%

= 0.4/100

= 1/250

Solve for the portion (in $). Round to hundredths when necessary.

9 1/2% of $400 = 19/2% x 400

= 0.095 x 400

= 38

Solve for the portion. Round to hundredths when necessary.

What number is 253% of 2,500?

253/100 x 2500

= 2.53 x 2500

= 6325

3 0

4 years ago

How do I complete these questions a bit confused . (extra credit work )

otez555 [7]

Answer:

(1)

$a = \frac{3\sqrt 3}{2}$

$b = \frac{3}{2}$

(2)

$a = \sqrt 6$

$b = \sqrt 2$

Step-by-step explanation:

Solving (1):

Considering

$\theta = 60^o$

We have:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

This gives:

$\sin(60^o) = \frac{a}{3}$

Solve for a

$a = 3 * \sin(60^o)$

$\sin(60^o) = \frac{\sqrt 3}{2}$

So:

$a = 3 * \frac{\sqrt 3}{2}$

$a = \frac{3\sqrt 3}{2}$

To solve for b, we make use of Pythagoras theorem

$3^2 = a^2 + b^2$

This gives

$3^2 = (\frac{3\sqrt 3}{2})^2 + b^2$

$9 = \frac{9*3}{4} + b^2$

$9 = \frac{27}{4} + b^2$

Collect like terms

$b^2 = 9 - \frac{27}{4}$

Take LCM and solve

$b^2 = \frac{36 - 27}{4}$

$b^2 = \frac{9}{4}$

Take square roots

$b = \frac{3}{2}$

Solving (2):

Considering

$\theta = 60^o$

We have:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

This gives:

$\sin(60^o) = \frac{a}{2\sqrt 2}$

Solve for a

$a = 2\sqrt 2 * \sin(60^o)$

$\sin(60^o) = \frac{\sqrt 3}{2}$

So:

$a = 2\sqrt 2 * \frac{\sqrt 3}{2}$

$a = \sqrt 2 * \sqrt 3$

$a = \sqrt 6$

To solve for b, we make use of Pythagoras theorem

$(2\sqrt 2)^2 = a^2 + b^2$

This gives

$(2\sqrt 2)^2 = (\sqrt 6)^2 + b^2$

$8 = 6 + b^2$

Collect like terms

$b^2 = 8 - 6$

$b^2 = 2$

Take square roots

$b = \sqrt 2$

3 0

3 years ago