Answer:
x ∈ [-2, 7]
Step-by-step explanation:
The given equation ...
x^2 -5x -4 ≤ 10
can be rewritten as ...
x^2 -5x -14 ≤ 0
and factored as ...
(x +2)(x -7) ≤ 0
Clearly, the "or equal to" condition will be met when x=-2 and x=7. For values of x between these numbers, one factor is negative and the other is positive. Hence the product will be negative. So, numbers in that interval are the solution set.
x ∈ [-2, 7]
(5y - 1) + (-2y + 4) = 5y - 1 - 2y + 4
= 5y - 2y - 1 + 4
= 3y + 3 [OPTION B]
Answer:
Step-by-step explanation:
Given function : 4x³ + ln(y²) + 2y = 2x
on differentiating both sides with respect to 'x', we get
or
or
or
or
or
or
Answer:
Step-by-step explanation:
Using first equation in the second gives you
x-3(-2x+1)=11
x+6x-3=11
7x-3=11
7x=14
x=2, making y=-2x+1 become
y=-2(2)+1
y=-4+1
y=-3 so the solution is the point
(2,-3)