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3 years ago

This data can best be modeled with

Mathematics

1 answer:

Fed [463]3 years ago

4 0

9514 1404 393

Answer:

c) exponential

Step-by-step explanation:

Each y-value is half the previous one, so an exponential function is indicated.

y = 12800(1/2)^x

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Use the formula R = 6e12.77x, where x is the blood alcohol concentration and R, as a percent, is the risk of having a car accide

tester [92]

$R=6e^{12.77x}$
$50=6e^{12.77x}$
$\frac{50}{6}= e^{12.77x}$
$log \frac{50}{6}=log( e^{12.77x})$
$0.920818754=12.77x$
$x=0.07$

6 0

3 years ago

Read 2 more answers

Given: x+2y=-6<br> Solve for y

yuradex [85]

Answer:

y = -3 - 1/2 x

Step-by-step explanation:

subtract x from both sides and divide by 2

5 0

3 years ago

Write an equation for the inverse:<br> f(x) = x-10/5

Hatshy [7]

Answer:

5x+10

Step-by-step explanation:

let f(x)=(x-10)/5=y

now write 'x' in term of y

i.e, x-10=5y

i.e, x=5y+10

now replace y with x to get required inverse of f(x)

=5x+10

8 0

3 years ago

Suppose that a poll finds that 31.9% of taxpayers who filed their tax return electronically self-prepared their taxes. If thre

Aneli [31]

Answer: 0.0325

Step-by-step explanation:

Binomial probability distribution formula for x successes in n trials:-

$P(X=x)=^nC_x\ p^x\ (1-p)^{n-x}$ , where n is the number of trials , p is the probability of success.

Given : The probability that taxpayers who filed their tax return are electronically self-prepared their taxes : $p= 0.319$

If three tax returns submitted electronically are randomly selected, then the probability that all three were self-prepared is given by :-

$P(X=3)=^3C_3\ (0.319)^3\ (1-0.319)^{3-3}\\\\=(1) (0.319)^3(1)\\=0.032461759\approx0.0325$

Hence, the probability that all three were self-prepared =0.0325

6 0

3 years ago

ASAP NEED HELP PLEASE

Katen [24]

Answer:

line n has slope equal to zero

7 0

3 years ago