we know that
The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.
The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.
If the probability that any one egg has 1/6 chance of salmonella
then
the probability that any one egg will not have salmonella = 5/6.
Therefore
for all 5 to not have salmonella
= (5/6)^5 = 3125 / 7776
= 0.401877 = 0.40 to 2 decimal places
REMEMBER this is the probability that NONE have salmonella
Therefore
the probability that at least one does = 1 - 0.40
= 0.60
the answer is
0.60 or 60%
Answer:
Step-by-step explanation:
the sequence is exponential and the formula is f(n) 16 -r/16-1
Answer:
Step-by-step explanation:
0.00048*.81=0.0003888
0.0003888*10=0.003888
0.003888*(10)=0.3888
0.3888-7=-6.6112
-6.6112*0.027=-224.8592593
-224.8592593*0.04= -9.794370372
-9.794370372*(10)=-97.94370372
-97.94370372*6= -587.6622223
