Answer:
a) 0.264
b) 48 cubit light-years
Step-by-step explanation:
For calculating a) What is the probability of 3 or more stars in 16 cubic light years?
a)
λ= 1 star/16 cubic light-years
t= measure t in units of 16 cubic light years.
E(Y) = λ t = (1/16)(16) = 1 star
P(X>=2) = 1 - P(X<2)
= 1 - [e^-1 + (e^-1)(1)/1!]
= 0.264
b)
P(X≥1) = 1 - P(X=0)
= 1 - e^-μ
0.95 = 1 - e^-μ
e^-μ = 1 - 0.95
e^-μ = 0.05
ln(e^-μ) = ln(0.05)
-μ = -3
μ = 3
Therefore 3 x 16 = 48 cubic light years of space
7x + 5 = 2x - 35
=> 7x - 2x = - 35 - 5
=> x( 7 - 2 ) = - ( 35 + 5 )
=> x( 5 ) = - ( 40 )
=> x × 5 = - 40
x = 5
Therefore the value of x in the given equation 5
Answer:
2
Step-by-step explanation:
To solve this equation, you need to convert 2 1/2 into an improper fraction:
2 1/2 = 5/2
Then, you convert this into 6ths:
5/2 = 15/6
Next, you divide 15/6 by 5/6:
15/6 / 5/6 = 3
Because Jamal wouldn't make a stop at the end (it wouldn't be considered a stop because he is done), you subtract 1:
3-1=2
The answer is 2 (hope this helps, sorry if i got it wrong)
Answer:
given : 0.61 per year
formula poisson probability : p(x=k)=xke-x/k!
(a) The parameter λ is the product of the rate per year and the number of years. The number of years is 1 year in this case.
λ=0.61×1=0.61
Evaluate the formula of the Poisson probability at k=0,1:
P(X=0)= 0!
(0.61)
0
e
−0.61
≈0.5434
P(X=1)=
1!
(0.61)
1
e
−0.61
≈0.3314
Add the corresponding probabilities:
P(X≤1)=P(X=0)+P(X=1)=0.5434+0.3114=0.8748
Use the complement rule:
P(X>1)=1−P(X≤1)=1−0.8748=0.1252
Note: The solution in the back of the book is the probability of at least one death instead of more than 1 death, thus the solution in the back of the book is not correct.
Step-by-step explanation:
this is prob wrong so im sorry in advance!
