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2 years ago

I need to find x in these two problems in the picture.

Mathematics

2 answers:

JulijaS [17]2 years ago

8 0

1st one- 1.5
2nd one- 2.25

forsale [732]2 years ago

4 0

Answer:

for the first one do 15 divided by 10 and the second one 18 divided by 8.

Step-by-step explanation:

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Round 419,825,312 to the nearest million

denis23 [38]

Answer:

6,852,780

Step-by-step explanation:

7 0

3 years ago

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What is 4z-3/z+6 when z = −3?

Ierofanga [76]

4(-3)-3/(-3)+6
-12-3/-3+6
-12+1+6
-12+7
-5

3 0

3 years ago

PLS HELP ASAP!!<br> Choose the correct answer:

Gemiola [76]

Im late do you still need the answer aa it wont send aaa

4 0

3 years ago

3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k

Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

$\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt$

Evaluate the integral to solve for y :

$\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt$

$\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x$

$\displaystyle y = x^3+2x^2+kx - 2$

Use the other known value, f(2) = 18, to solve for k :

$18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}$

Then the curve C has equation

$\boxed{y = x^3 + 2x^2 + 2x - 2}$

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

$\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2$

The slope of the given tangent line $y=x-2$ is 1. Solve for a :

$3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1$

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

$x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1$

So, the point of contact between the tangent line and C is (-1, -3).

7 0

2 years ago

Jen measured the growth of a sunflower in one week it grew 2 and 1 half in

Pie

So you basically add the amount it grew each week. So week one is 2 and 1/2, week two is 2 and 3/4 and week three is 3 and 1/4. to make things simpler, add week two and three which gets you 6inches, then add week one, to get 8 and a half inches.

8 0

3 years ago