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Anuta_ua [19.1K]
3 years ago
12

Determining function values from a graph

Mathematics
1 answer:
professor190 [17]3 years ago
6 0

Answer:

The y value of a point where a vertical line intersects a graph represents an output for that input x value. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because that x value has more than one output.



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PLEASE HELP I AM BEGGIN YOU EXTRA POINTS AND BRAINLIEST PLEASE !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
S_A_V [24]

Answer:

The answer is 1.8%

Step-by-step explanation:

I used the A=PRT equation

4 0
3 years ago
Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being
Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of​ weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new​ equipment, and this sample has a standard deviation of 0.047.

Let \sigma = <u><em>standard deviation of weights of new equipment.</em></u>

SO, Null Hypothesis, H_0 : \sigma \geq 0.065      {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, H_A : \sigma < 0.065      {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here <u>One-sample chi-square</u> test statistics;

                           T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s = sample standard deviation = 0.047

           n = sample of quarters = 25

So, <u><em>the test statistics</em></u>  =  \frac{(25-1)\times 0.047^{2} }{0.065^{2} }  ~  \chi^{2}__2_4   

                                     =  12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0
3 years ago
Justin launches a rocket straight up into the air. The table below gives the height(t) of the rocket (in meters) at a few times
Papessa [141]

Using it's formula, the average rates of change are given as follows:

a) 30 meters per second.

b) -10 meters per second.

<h3>What is the average rate of change of a function?</h3>

The average rate of change of a function is given by the <u>change in the output divided by the change in the input.</u> Hence, over an interval [a,b], the rate is given by the following equation:

r = \frac{f(b) - f(a)}{b - a}

For item a, taking the data from the table, we have that:

  • f(0) = 0.
  • f(4.6) = 138.

Hence the rate is given as follows:

r = (138 - 0)/(4.6 - 0) = 30 meters per second.

For item b, taking the data from the table, we have that:

  • f(9.2) = 23.
  • f(11.5) = 0.

Hence the rate is given as follows:

r = (0 - 23)/(11.5 - 9.2) = -10 meters per second.

More can be learned about the average rate of change of a function at brainly.com/question/11627203

#SPJ1

3 0
1 year ago
A car was sold 24 standard washed in a day , which was 25% of their total sales for that day . What was the total amount of wash
-Dominant- [34]

Answer:

96

Step-by-step explanation:

GIVEN: A car was sold 24 standard washed in a day , which was 25\% of their total sales for that day.

TO FIND: Total amount of washes that the car wash sold that day.

SOLUTION:

Let the total sales of car washes sold for that day =x

total number of standard car washes sold s=24

As, total standard car washes sold are 25\% of total sales in a day

s=\frac{25}{100}x

putting value in equation

24=\frac{25}{100}x

x=\frac{24}{25}\times100

x=96

Hence the total  number of car washes sold that day are 96

4 0
4 years ago
The number of bagels sold daily for two bakeries is shown in the table:
ivann1987 [24]

Going by the data given, the best center of distribution to use in terms of mean and median is D) Mean for Bakery A because the data is symmetric; median for Bakery B because the data is not symmetric.

<h3>What centers of distribution should be used?</h3>

The mean should be used for data sets that are symmetric while the median should be used for data that is not symmetric.

The data is said to be symmetric when the mean and median are equal or very close.

Bakery A mean:

= (45 + 52 + 51  48 + 61 + 34 + 55  46) / 8

= 49

Bakery A median is 49.5

Bakery B mean:

= (48  42 + 25  45 + 57 + 10 + 43 + 46 ) / 8

= 39.5

Bakery B median is 44.

This shows that Bakery A data is symmetric so the best center of distribution to use is mean.

Bakery B is not symmetric so the center of distribution to use is median.

Find out more on symmetric data at brainly.com/question/7130507

#SPJ1

8 0
2 years ago
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