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yan [13]
2 years ago
6

Find the SIDE LENGTH of the garden,

Mathematics
1 answer:
Otrada [13]2 years ago
6 0
If the garden is square it would be 8 square feet.
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(25 points & Brainliest, please explain)
My name is Ann [436]

Answer:

Quadratic expression

Step-by-step explanation:

5x + 3x^2 − 7

Degree of expression = 2

So it is Quadratic expression

6 0
3 years ago
Read 2 more answers
1) what is the answer to<br><br> (5²-7) ₃ 3
valentinak56 [21]

Answer: 54

Explanation step by step: according to bidmas you must open the bracket first before any other thing. so the solution is 5×5-7×3

8 0
3 years ago
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Correct answer gets Brainliest! Solve for x.
Simora [160]

Subtract 13 from both sides:

-7-13 \geq -5x

-20 \geq -5x

Divide both sides by -5. Since this is a negative number, you have to invert the inequality sign:

4 \leq x

Which means

x \geq 4

4 0
3 years ago
Read 2 more answers
What is the mystery number? It is less then 40. You say its name when you start at 3 and count by 3s.You say its name when you s
wariber [46]

Answer:

The number must be 30.

Step-by-step explanation:

The mystery number is less then 40.

You say its name when you start at 3 and count by 3s. This means that it is a multiple of 3.

You say its name when you start at 5 and count by 5s. This means that it is a multiple of 5.

The only two numbers that are multiples of 3 and 5 and less than 40 are 15 and 30.

Since we have been told that the number is not 15, the number must be 30.

8 0
3 years ago
The safe load, L, of a wooden beam supported at both ends varies jointly as the width, w, and the square of the depth, d, and in
MakcuM [25]

Answer:

joint variation means L (safe load) is directly proportional to both w and d2

inverse proportionality means L = k/l

So the equation is:

L = k(wd2/l)

You are given:

w = 6 in

d = 5 in

l = 12 ft

L = 7666 lbs

7666 = k(6*52/12)

Solve for the constant, k.

7666 = k (6*25/12)

7666 = k (150/12)

7666 = k (12.5)

613.28 lbs/(ft.in3) = k

Use this k-value to solve for L in the last part of the question.

What safe load, L would a beam 3 in. wide, 7 in. deep and 15 ft long of the same material support? (Round off your answer to the nearest pound.)

w = 3 in

d =7 in

l = 15 ft

k = 613.28 lbs/(ft.in3)

Final Safe load = 6010.144 lbs *** Edited for clarity and to fix a multiplication erro

5 0
1 year ago
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