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EastWind [94]
3 years ago
15

A girl 1.0 m in height, standing on top of a vertical building 45.0 m high sees a car some distance away when the angle of depre

ssion is 55 degree. What distance is the car from the base of the building? ​
Mathematics
2 answers:
zavuch27 [327]3 years ago
5 0

Answer:

55

Step-by-step explanation:

bjn mjjm

Pachacha [2.7K]3 years ago
4 0
65.5, is the answer I could be wrong tho
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What is the value of z in the equation 2z + 6 = –4? (5 points) <br> 5 <br> 1 <br> –1 <br> –5
PtichkaEL [24]
The answer is -5. Hope this helps.
6 0
3 years ago
Read 2 more answers
A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be
irga5000 [103]

Answer:

The statement is now presented as:

\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

Step-by-step explanation:

Let C = (h,k) the coordinates of the center of the circle, which must be transformed into C'=(h', k') by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

(x-h)^{2}+(y-k)^{2} = r^{2}

Where r is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) <em>Center of the circle is translated 4 units to the right</em> (+x direction):

C''(x,y) = C(x, y) + U(x,y) (Eq. 1)

Where U(x,y) is the translation vector, dimensionless.

If we know that C(x, y) = (h,k) and U(x,y) = (4, 0), then:

C''(x,y) = (h,k)+(4,0)

C''(x,y) =(h+4,k)

2) <em>Reflection over the x-axis</em>:

C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)] (Eq. 2)

Where O(x,y) is the reflection point, dimensionless.

If we know that O(x,y) = (h+4,0) and C''(x,y) =(h+4,k), the new point is:

C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]

C'(x,y) = (h+4, 0)-(0,k)

C'(x,y) = (h+4, -k)

And thus, h' = h+4 and k' = -k. The statement is now presented as:

\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

<em />

4 0
3 years ago
A right circular cylinder has a base area of 110 square inches and a volume of 1650 cable loches. What is the height, in inches,
denpristay [2]

Answer:

height = 15 inches

Step-by-step explanation:

the volume (V) of a cylinder is calculated as

V = Ah ( A is the base area and h the height )

given V = 1650 and A = 110 , then

1650 = 110h ( divide both sides by 110 )

15 = h

3 0
2 years ago
Can someone please tell me the reason ASAP!!<br> Thank you❤️!
Sav [38]

Answer:

because base angle of isoscels triangle is congurent.

if one base is right angle then both base be rightangle.

8 0
3 years ago
Consider the following expression and determine which statements are true.
Serhud [2]

Given:

$\frac{7}{r}+2^{3}+\frac{s}{3}+11

To find:

Which statement are true?

Solution:

Option A: The entire expression is a sum.

It is true because it performed addition operation.

Option B: The coefficient of s is 3.

$\frac{7}{r}+2^{3}+\frac{s}{3}+11=\frac{7}{r}+2^{3}+\frac{1}{3}s+11

It is not true because the coefficient of s is \frac{1}{3}.

Option C: The term \frac{7}{r} is a quotient.

If we divide 7 by r, we obtain a quotient.

So it is true.

Option D: The term 2^3 has a variable.

It is not true because it does not contain any variable.

Therefore the entire expression is a sum and the term \frac{7}{r} is a quotient are true statement.

3 0
3 years ago
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