your answer would be 2x - y + 3 = 0
Step-by-step explanation:
s is inversely proportional to t
If s= 0.6 , t= 4
s=k/t
0.6= k/4
k=2.4
If s=12, then
t=k/s
t=2.4/12
t=0.05
The parts of a circle are the r<em>adius, diameter, circumference, arc, chord, secant, tangent, sector and segment.</em>
Radius:
The distance from the center to any point on the circle.
Diameter:
The distance across the circle through the center point.
Circumference:
The distance around a circle.
Arc:
arcs in the same circle that have exactly one point in common. measure of arc divided by 360 multiplied by the circumference. the length of an arc. semicircle. an arc that is half of a circle; always measures 180 degrees.
Chord:
a line segment that connects two points of a circle.
Secant:
A secant is a line that intersects a circle in two points.
Tangent:
A tangent is a line that intersects the circle in exactly one point.
Sector:
region bounded by an arc of a circle and the two radii to the arc's endpoints. - A sector is like a "pizza slice" of the circle. It consists of a region bounded by two radii and an arc lying between the radii.
Segment:
A segment or length of a segment with one endpoint at the center of the circle.
9514 1404 393
Answer:
d = 3√10 ≈ 9.487
Step-by-step explanation:
The distance formula is appropriate.
d = √((x2 -x1)^2 +(y2 -y1)^2)
d = √((-3 -0)^2 +(2 -(-7))^2) = √(9 +81) = √90
d = 3√10
Remark
There's a lot you don't know here. Are DE and GF parallel? Is B a right angle? You can't assume that it is. The safest way to proceed is to give x in terms of 58 and B. You might get an answer that gives you something like 32 but I don't think you can say that unless you are told somewhere that ABC is a right angle triangle with the right angle at B.
So what to do.
<BAC = 58o That's because <BAC = <IAK They vertically opposite.
<ABC + <BAC + <ACB = 180o All triangles have 180o
<ACB = 180 - 58 - <ABC Solve for an unknown angle of a triangle.
<ACB = 122 - <ABC
x = <ACB Vertically opposite angles.
x = 122 - <ABC Answer It's 32 if ABC is a right angle.