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pentagon [3]
3 years ago
7

Antoine Purchase 1.8 kg of apples and 315 dekagrams of oranges This was 1350 g more than the weight of bananas bridges what was

the way of the bananas Antonio purchased in grams
Mathematics
1 answer:
victus00 [196]3 years ago
6 0

Answer: 3600 grams

Step-by-step explanation:

A dekagram means 10 grams.

1 kilogram = 1000 grams

Therefore the total number of grams when Antoine Purchase 1.8 kg of apples and 315 dekagrams of oranges will be:

= (1.8 × 1000) + (315 × 10)

= 1800 + 3150

= 4950 grams

Since this was 1350g more than the weight of bananas, the weight of the bananas Antonio purchased in grams will be:

= 4950 - 1350

= 3600 grams

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Tina paid $6.60 for some $0.15 stamps and some $0.20 stamps. She bought 37 stamps in all. How many of each kind did she buy?
sergiy2304 [10]

Answer:

Let n be the number of 25 cent stamps.Then, 28 - n must be the number of 29 cent stamps.Tim paid $7.60 the stamps.

0.25n + 0.29(28 - n) = 7.60

This means that n stamps at 25 cents a piece plus (28 - n) stamps at 29 cents a piece sum to $7.60.Solve for m.

0.25n + 8.12 - 0.29n = 7.60

-0.04n = -0.52

n = 13

So, Tim bought 13 25-cent stamps and 28 - 13 = 15 29-cent stamps

Step-by-step explanation:

hope this helps:)

4 0
2 years ago
A random sample of 85 sixth-graders in a large city take a course designed to improve scores on a reading comprehension test. Ba
BartSMP [9]

Answer:

12.6 < \mu < 14.8

For this case we can find the margin of error like this:

ME= \frac{14.8-12.6}{2}= 1.1

Since we need to divide the width of the interval by 2.

And now with the margin of error we can find the sample mean with any of the two following ways:

12.6 +1.1=13.7

14.8-1.1=13.7

So for this case the correct answer would be:

A. Sample Mean = 13.7; Margin of Error = 1.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=85-1=84

We know that the confidence interval is given by:

12.6 < \mu < 14.8

For this case we can find the margin of error like this:

ME= \frac{14.8-12.6}{2}= 1.1

Since we need to divide the width of the interval by 2.

And now with the margin of error we can find the sample mean with any of the two following ways:

12.6 +1.1=13.7

14.8-1.1=13.7

So for this case the correct answer would be:

A. Sample Mean = 13.7; Margin of Error = 1.1

3 0
2 years ago
What is this answer?
Shtirlitz [24]

Answer:

1/2

Step-by-step explanation:

your mom :|

4 0
2 years ago
Read 2 more answers
A recipe for banana bread requires 3 cups of bananas for every 1 1/2 cups of sugar used. At this rate how many cups of sugar sho
mr Goodwill [35]

Answer:

The answer is 1 cup of sugar

Step-by-step explanation:

x = 2 x 1.5/3

x = 3/3

x = 1 cup of sugar

hope it helps!

4 0
3 years ago
If cosA+sinA=√2, then prove A=45°.
Lyrx [107]

Answer:

1/2 now substitute 45 degrees

Step-by-step explanation:

6 0
2 years ago
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