Rewrite the following expression with rational exponents. 3 sq root -27x^2 y^7 Show your work
1 answer:
Answer:
Step-by-step explanation:
The square root is possible only if y≤0
if y>0 the expression lose meaning, in fact (-)(+)(+) = (-) and a square root of a negative number doesn’t exist. x^2 is a square so it is ever positive if x is not 0
if y≤0 can be rewritten as:
3(-27x^2y^7)^1/2
or if we want simplify the expression:
^1/2
we have to put the symbol of absolute value between x and y because a x^2 and y^6 are numbers that are ever positive, while x and y^3 can be also negative. Thanks to the simbol of absolute value we can “force” them to be positive
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Answer:
n = 20
Step-by-step explanation:
The number of diagonal that can be drawn in a polygon of n sides is given by :
If the number of diagonals are 230, then put D = 230 in above formula. So,
It is a quadratic equation, the value of n is equal to 20.
It means that for 230 diagonal, there are 20 sides of the polygon.
Remember
difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
and the undistributiv propeoryt
ab-ac=a(b-c)
so we have
undistribute and factor
cancel out the one ( (u-2)/(u-2)=1)
is result
difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
and the undistributiv propeoryt
ab-ac=a(b-c)
so we have
undistribute and factor
cancel out the one ( (u-2)/(u-2)=1)