Rewrite the following expression with rational exponents. 3 sq root -27x^2 y^7 Show your work
1 answer:
Answer:
Step-by-step explanation:
The square root is possible only if y≤0
if y>0 the expression lose meaning, in fact (-)(+)(+) = (-) and a square root of a negative number doesn’t exist. x^2 is a square so it is ever positive if x is not 0
if y≤0 can be rewritten as:
3(-27x^2y^7)^1/2
or if we want simplify the expression:
^1/2
we have to put the symbol of absolute value between x and y because a x^2 and y^6 are numbers that are ever positive, while x and y^3 can be also negative. Thanks to the simbol of absolute value we can “force” them to be positive
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Hi! Basically, the problem is asking us to find the values of a, b, and c in the equation 
. Since we have three unknowns, we just need three equations. We can find these equations by using the data in the table.
First let's plug x = 0 and f(x) = 0.
Now that we know c, it's time to pick two more pairs. Let's plug-in (2,78) and (4,152)
Before proceeding with the process of eliminating one variable, let us first reduce both equations to their lowest terms. We divide the first equation by 2 and we divide the second one by 4.
Next, we subtract equation 2 from equation 1.
Finally, we substitute the value of a to equation 2 to get the value of b.
Therefore, the function should be
First let's plug x = 0 and f(x) = 0.
Now that we know c, it's time to pick two more pairs. Let's plug-in (2,78) and (4,152)
Before proceeding with the process of eliminating one variable, let us first reduce both equations to their lowest terms. We divide the first equation by 2 and we divide the second one by 4.
Next, we subtract equation 2 from equation 1.
Finally, we substitute the value of a to equation 2 to get the value of b.
Therefore, the function should be