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ohaa [14]
3 years ago
15

Find the volume of a cylinder whose base is an ellipse with axes of 12 inches and 7 inches. The altitude of the cylinder is 21 i

nches. Round to the nearest tenth of a cubic inch. A. 1,522.41 in3 B. 1,866.45 in3 C. 1,385.45 in3 D. 1,213.12 in3
Mathematics
1 answer:
Tpy6a [65]3 years ago
3 0

if the ellipse has a major axis of 12 inches, that means its major radius is half that, or 6, and if its minor axis is 7, then its minor radius is half that, 3.5.


\bf \textit{volume of an elliptical cylinder}\\\\
V=\pi ab h~~
\begin{cases}
a=\textit{major axis radius}\\
b=\textit{minor axis radius}\\
h=height\\[-0.5em]
\hrulefill\\
a=6\\
b=3.5\\
h=21
\end{cases}
\\\\\\
V=\pi (6)(3.5)(21)\implies V\approx 1385.44236023309881816203

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What is the area of the triangular base?
Ludmilka [50]

Answer:

90cm2

Step-by-step explanation:

1/2x base x height.

1/2 x10 x 18

90cm2

4 0
2 years ago
I do not understand
Ivenika [448]
A) 1
B) 10/3
C) 6
D) 18/5
So only C is bigger than 4
4 0
2 years ago
Read 2 more answers
What is the answer to this?
alexdok [17]

Answer:

  1. x < 2.5
  2. x > 2.5

Step-by-step explanation:

One way to do this is to try a number for x and see if it makes the inequality true. A suitable number here is x=0. This value of x is less than 2.5.

<h3>1.</h3>

For x=0, you have ...

  5 > -5 . . . . . true; the solution space is x < 2.5

__

<h3>2.</h3>

For x=0, you have ...

  -25 > -5(2.5)

  -25 > -12.5 . . . . . false; the solution space is x > 2.5

_____

<em>Alternate solution</em>

<h3>1.</h3>

Subtract 5:

  -4x > -10

Divide by -4

  x < 2.5

__

<h3>2.</h3>

Divide by -5:

  5 < x +2.5

Subtract 2.5

  2.5 < x

  x > 2.5

6 0
2 years ago
Plsss hElpp!!!!! TY!!
kari74 [83]

Given:

A circle with diameter 9 cm.

To find:

The area of the circle.

Solution:

The area of a circle is:

A=\pi r^2                   ...(i)

Where r is the radius.

We know that, the diameter of a circle is twice than its radius.

The diameter of the given circle is 9 cm.

r=\dfrac{9}{2}

r=4.5

Substituting r=4.5, \pi =3.14 in (i), we get

A=(3.14)(4.5)^2

A=(3.14)(20.25)

A=63.585

A\approx 63.6

Therefore, the area of the given circle is 63.6.

4 0
3 years ago
2x + 8y = 5<br> 24x – 4y = –15
slega [8]

2x + 8y = 5

2/ 24x - 4y = -15

2x + 8y = 5

48x - 8x = -30

+

--------------------------

50x = -25

x = -1/2

2 * -1/2 + 8y = 5

-1 + 8y = 5

8y = 6

y = 6/8

y = 3/4

x = -1/2 y = 3/4

5 0
3 years ago
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