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3 years ago

Plz help with this question

Mathematics

2 answers:

Anton [14]3 years ago

5 0

Answer:

x + 5 = -4

x = -9

~theLocoCoco

Papessa [141]3 years ago

5 0

Answer:

An equation = 5 > x = -4

Step-by-step explanation:

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What is equivalent to 5y+2y+6x+2y-x

astra-53 [7]

Your answer would be C. 5x+9y. <em>If you combine like terms and subtract the variable you will get your correct answer. I hope this helps.</em>

3 0

3 years ago

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A colony of cats were introduced into a reserve. The number of cats present at timet(measured in years since the colony was intr

RUDIKE [14]

ANSWER:

a) 12 cats

b) 232

c) 246

d) 14

EXPLANATION:

Given the expression for number of cats C present at time t:

$C\text{ = }\frac{12.31}{0.05+0.56^t^{}}$

a) To find the number of cats initially on the reserve, let t = 0

Therefore, substitute 0 for t in the equation

$\begin{gathered} C\text{ = }\frac{12.31}{0.05+0.56^0} \\ \text{ = }\frac{12.31}{0.05\text{ + 1}} \\ \text{ = }\frac{12.31}{1.05} \\ =\text{ }11.72 \end{gathered}$

Number of cats initially on the reserve are approximately 12 cats

b) C(10):

$\begin{gathered} C(10)\text{ = }\frac{12.31}{0.05+0.56^{10}}\text{ = 232.12} \\ \end{gathered}$

C(10) = 232

Here, C(10) means that C is a function of 10. This means at time = 10 years

C)Using function notation to express the number of cats present after 17 years, we have:

$C(17)\text{ = }\frac{12.31}{0.05+0.56^{17}}$

$C(17)\text{ = }\frac{12.31}{0.05+0.56^{17}}\text{ = }245.94$

Therefore, number of cats present after 17 years are approximately 246 cats

C(17) = 246 cats

d) In this case, first find the number of cats present in the 10th year and subtract from the number of cats present in the 17th year.

$C(10)\text{ = }\frac{12.31}{0.05+0.56^{10}}=\text{ }232.12$

From question C above, we know C(17) = 246

Therefore, the increase in cat population to be expected from the 10th year to the 17th year is:

C(17) - C(10) = 246 - 232 = 14 cats

7 0

1 year ago

PLEASE HELP I WILL REWARD BRAINLY. PLEASE ONLY ANSWER IF YOU KNOW HOW TO SOLVE THIS PROBLEM. PLEASE INCLUDE INSIGHTFUL EXPLAINAT

DochEvi [55]

Answer:

40 inches

Step-by-step explanation:

<h3>Left side of seesaw:</h3>

Woman + sit = 145 lb + 5 lb = 150 lb

Distance from the fulcrum to the left side = 60 in

<u>Moment of the force on the left side:</u>

150*60 = 9000

<u />

<h3>Right side of seesaw:</h3>

Son + sit = 95 lb + 5 lb = 100 lb

Distance from the fulcrum to the son's seat = 60 in

<u>Moment of the force:</u>

100 * 60 = 6000

Daughter + sit = 70 lb + 5 lb = 75 lb

Distance from the fulcrum to the daughter's seat = x

<u>Moment of the force:</u>

75 * x

Since left and right sides are balanced, moments should be equal on both sides.

<u>This is shown as:</u>

75x+6000= 9000
75x= 3000
x= 3000/75
x= 40

So, the daughter should sit at 40 in distance from the fulcrum.

5 0

4 years ago

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Explain how many thirds are in 7

gladu [14]

The answer is 21 all you had to do was multiply 7 by 3

4 0

3 years ago

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5 = 4a - 7<br> 3 - 8c = 35<br> -1/2x -7 = -11<br> Solve this please.

Hitman42 [59]

Answer:

a=3, c=-4, x=8

Step-by-step explanation:

5=4a-7

4a-7=5

4a=5+7

=12

a=12÷4

3-8c=35

-8c=35-3

=32

c=-32÷8

=-4

-1/2x-7=-11

-1/2x=-11+7

=-4

x=4÷1/2

=4/1×2/1

3 0

3 years ago