![A = \pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%20%5Cpi%20r%5E2)
radius = half the diameter ------> 16/2 = 8
![A = \pi (8^2) = 64 \pi](https://tex.z-dn.net/?f=A%20%3D%20%20%5Cpi%20%288%5E2%29%20%3D%2064%20%20%5Cpi%20)
pi = 3.14
64*3.14 = 201
Answer:
x is any Real number
Step-by-step explanation:
We first apply distributive property on the left to get rid of the grouping symbol, and then combining the like terms (linear terms on one side and numerical terms on the other side of the equation):
![8x+16=10x+13-2x+3\\16-13-3=10x-2x-8x\\0=0](https://tex.z-dn.net/?f=8x%2B16%3D10x%2B13-2x%2B3%5C%5C16-13-3%3D10x-2x-8x%5C%5C0%3D0)
This equation results on a TRUE equality Zero = Zero, which means that any value we use for "x" in the original expression will always render an equality.
Therefore x is any Real number.
Answer: 3/8 + 4/5 = <u>1 7/40</u>
4/5 = 32/40
3/8 = 15/40
32/40 + 15/40 = 47/40
47/40 = ![1\frac{7}{40}](https://tex.z-dn.net/?f=1%5Cfrac%7B7%7D%7B40%7D)
Hope this helped! Have a great day! :D
Answer:
1.1×10^-4
Step-by-step explanation:
we move the point from where to in between 1.1 and counts the number of numbers it has crossed..in this case it 4...which should be -4
Answer:
Proved!
Step-by-step explanation:
For two functions f(x) and g(x) to be inverses of each other then;
f(g(x)) = x and g(f(x)) = x condition must be satisfied.
<u>Checking: A. f(x) = 7x³ + 10 and g(x) = ∛</u>
<u />
<u />
So f(g(x)) = 7(
)³ + 10
We get; 7(
) + 10 = x - 10 + 10 = x (*<em>This is correct!)</em>
<em />
So g(f(x)) =
Ten cancels out and we are left with;
=
= x (* <em>This is also correct!)</em>