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vaieri [72.5K]
4 years ago
13

What is 6 pounds equal to in ounces?

Mathematics
2 answers:
V125BC [204]4 years ago
8 0

Answer: 96 ounces

Step-by-step explanation:

1 pound = 16 ounces

1 x 6 = 6 pounds

16 x 6 = 96 ounces

So in conclusion, 6 pounds = 96 ounces.

Hope this helps!

Ostrovityanka [42]4 years ago
4 0

Answer:

96

Step-by-step explanation:

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You might be interested in
MAn article is
Ray Of Light [21]

Answer:MAn article is

bought and sold at a profit of one fourth of selling

price. Find the profit percent.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the
Westkost [7]

Answer:

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

          <u>Left</u>      <u>Speed(km/h)</u>      <u>Time</u>

Car:   12PM            X  

Van:   12PM           60

Car/Van

DistanceCar        AB + z

DistanceVan       Az

Ratio:                  (AB+z)/Az  = 7/5

Time until both meet = T (in hours)

Distance Car:            xT

Distance Van:           60T

====

  xT = AB + z

  60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is:    time (hr) = 108 km/(84 km/h)

                                                 time = 1.286 hours

Distance for at 1.289 hours is:    distance (km) = (60 km/h)*(1.286 h)

                                                   distance = 77.14 km

At 1.286 hours, the car reverses direction.  The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours.  The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let <u>t</u> be the time <u>after</u> 1.286 hours that both vehicles meet/collide.

t*(60 km/h)  +  t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

==============

<u>CHECK</u>

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

<u><em>YES</em></u>

     

3 0
3 years ago
When a number is decreased by 19%, the result is 66. What is the original number to the nearest tenth?
murzikaleks [220]

Answer:

80

step by step explanation:

when a number is decreased by 19 %, u calculate backwards, making the % to 119% of 66. Hence it becomes 78.54 to be exact, but in the nearest tenth, it becomes 80.

4 0
3 years ago
Read 2 more answers
When 1,250 Superscript three-fourths is written in simplest radical form, which value remains under the radical?
Dvinal [7]

The value remains under the radical is 8 ⇒ last answer

Step-by-step explanation:

Let us revise how to write the exponent as a radical

  • a^{\frac{m}{n}} can be written as \sqrt[n]{a^{m}}
  • To simplify the radical factorize the base "a" to its prime factors

Example:

  • (54)^{\frac{2}{3}}=\sqrt[3]{(54)^{2}} ,
  • Factorize 54 into prime factors ⇒ 54 = 2 × 3 × 3 × 3 = 2(3)^{3}
  • \sqrt[3]{(54)^{2}}=\sqrt[3]{[2(3^{3}]^{2}}=\sqrt[3]{2^{2}*3^{6}}
  • 2² can not go out the radical because 2 is less than 3 not divisible by 3
  • 3^{6} can go out the radical because 6 is divisible by 3, then divide 6 by 3, so it will be 3² out the radical
  • \sqrt[3]{(54)^{2}}=3^{2}\sqrt[3]{2^{2}}=9\sqrt[3]{4}

Now let us solve your problem

∵ 1250^{\frac{3}{4}}=\sqrt[4]{1250^{3}}

- Factorize 1250 to its prime factors

∵ 1250 = 2 × 5 × 5 × 5 × 5

∴ 1250=2*5^{4}

∴ \sqrt[4]{(2*5^{4})^{3}}=\sqrt[4]{2^{3}*5^{12}}

∵ 2³ can not go out the radical because 3 < 4 and not divisible by it

- 5^{12} can go out the radical because 12 can divided by 4

∵ 12 ÷ 4 = 3

∴ 5^{12} can go out the radical as 5³

∴ \sqrt[4]{1250}=5^{3}\sqrt[4]{2^{3}}

∴ \sqrt[4]{1250}=125\sqrt[4]{8}

∴ The value remains under the radical = 8

The value remains under the radical is 8

Learn more:

You can learn more about the radicals in brainly.com/question/7153188

#LearnwithBrainly

8 0
3 years ago
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vovangra [49]
Property of zero as an exponent
4 0
3 years ago
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