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ratelena [41]
3 years ago
10

The point C(2,3) is translated along a vector that is parallel to the line y=3x-2. The translation vector has magnitude square r

oot of 10. What are the possible images of point C? Fill in as many answers as possible.
Mathematics
1 answer:
qaws [65]3 years ago
4 0

Step-by-step explanation:

The translation vector v can be resolved into its x and y components, where x² + y² = 10 (Pythagoras' Theorem) and y = 3x

(parallel to y = 3x - 2, slope = 3).

We have x² + (3x)² = 10,

=> x² + 9x² = 10, 10x² = 10, x = 1 or x = -1.

When x = 1, y = 3. When x = -1, y = -3.

Therefore 2 possible translation vectors

are (1, 3) or (-1, -3).

First new C' = (2 + (1), 3 + (3)) = (3, 6).

Second new C'= (2 + (-1), 3 + (-3)) = (1, 0).

The possible images are (3, 6) and (1, 0).

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hjlf

Answer:

0.01

Step-by-step explanation:

you just have to do the opposite. Since the is n*-5/8 you want to use inverse operation and do -0.4 divided by -5/8 when you do that you end up with 0.01. So the value of n is 0.01

5 0
3 years ago
Help please I need help
kirza4 [7]
Move the constant to the right by adding it’s opposite to both sides
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4 years ago
Factor the expression.
tiny-mole [99]
B. (k+10f)(k-5f) you can tell in 2 ways.  1. if the second sign is neg then the signs in the factors are going to be one neg and one positive so that knocks out C and D.  Then you look at the second term and since the 5 is positive then the 10 has to be positive so you end up with a positive 5kf.

The second way is to FOIL them out.  When you check B you get k^{2} -5kf+10kf- 50f^{2} combine your like terms and you have your original expression of k^{2} +5kf-50 f^{2}

Hope that helps
3 0
3 years ago
Points B, D, and F are midpoints of the sides of ΔACE. EC = 38 and DF = 16. Find AC. The diagram is not to scale.
Lunna [17]

Answer: The measure of AC is 32.

Explanation:

It is given that the Points B, D, and F are midpoints of the sides of ΔACE. EC = 38 and DF = 16.

The midpoint theorem states that the if a line segments connecting two midpoints then the line is parallel to the third side and it's length is half of the third side.

Since F and D are midpoints of AE and EC respectively.

So by midpoint theorem length of AC is twice of DF.

AC=2\times DF

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Therefore, the length of AC is 32.

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