A
It is a first degree polynomial (aka linear because its highest power is 1) and it has two terms (2x and 8)
It does not have eight terms and is not a monomial (one term ie 3x^2)
Answer:
r = va/(e - v)
Step-by-step explanation:
v = er/(r + a)
vr + va = er
va = er - vr
va = r(e - v)
r = va/(e - v)
Answer:
(-b/2a, b^2/(4*a) - b^2/2a + c)
Step-by-step explanation:
For a general parabola:
y = a*x^2 + b*x + c
We can write the vertex as:
(h, k)
The x-value of the vertex is the value of the axis of symmetry.
Then we have:
h = x = -b/2a
Now we need to find the y-value of the vertex.
To do that, we just replace the variable "x" by the x-value of the vertex in our equation, so we get:
k = y = a*(-b/2a)^2 + b*(-b/2a) + c
k = b^2/(4*a) - b^2/2a + c
Then the coordinates of the vertex are:
(h, k) = (-b/2a, b^2/(4*a) - b^2/2a + c)
If it's just the 7 that's repeating, let
<em>x</em> = 0.1777...
Then
10<em>x</em> = 1.777...
100<em>x</em> = 17.777...
100<em>x</em> - 10<em>x</em> = 17.777... - 1.777...
90<em>x</em> = 16
<em>x</em> = 16/90 = 8/45
If both 1 and 7 are repeating, let
<em>x</em> = 0.171717...
Then
100<em>x</em> = 17.171717...
100<em>x</em> - <em>x</em> = 17.171717... - 0.171717...
99<em>x</em> = 17
<em>x</em> = 17/99
The answer is 41.41
Since we know the side that is opposite to a, and the hypotenuse, we have enough information to get the cosine of a. The cosine is 45/60. If we know the cosine of an angle, we can get the arccos of that value to get the angle. The arccos of 45/60 is about 41.41.
