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3 years ago

Write an equation you could use to find the length of the missing side of the right triangle.

Mathematics

1 answer:

valentina_108 [34]3 years ago

6 0

The third one, b^2 = 22^2 - 7^2

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Pls help !!!!!!!!!!!!!!!!!!

Mashutka [201]

Maybe the answer is B

4 0

3 years ago

Can someone help me with this? thank you!

hammer [34]

Answer:

240cm³

Step-by-step explanation:

To find our answer we will multiply the volume, width, and height.

4 · 20 · 3 = 240. Therefore, 240cm³ is our answer.

Have a good day!

3 0

2 years ago

Read 2 more answers

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

6 0

3 years ago

Read 2 more answers

9966 [12]

The answer will be x=23

6 0

2 years ago

The points (3,9) and (-3,-9) are plotted on the coordinate plane using the equation y= a•x. What is the value of a?

8_murik_8 [283]

A=3

The equation y=3x goes through both points

Hope I helped

5 0

3 years ago