The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.
<h3>What is the distance the spaceship travels in 4 minutes?</h3>
The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;
Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.
Consequently, we can evaluate the distance travelled after 4 minutes as;
Distance = 200 × 4 = 800mi.
Ultimately, the distance travelled per minute by the spaceship is; 800mi.
Remarks:
600 miles
520 miles
800 miles
1,080 miles
Read more on ratios;
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Answer:
a. Draw a column for each ticket sold. (For 0-9, draw a bar upto 2. For 10-19, draw a bar upto 4. For 20-29, draw a bar upto 3. And for 30-39, draw a bar upto 1.
b. 10 students sold tickets
c. 40% of students sold 20 or more tickets
Yes it is because 2 sides would be the legs while 1 side is the hyptonuese so in this case 4 is a leg and 14 and 17 is the hyptonuese
Answer:
27 feet.
Step-by-step explanation:
Graph the quadratic equation, then find the point on the graph which aligns with x=3. Y would equal 27.
Answer:
0.71. with the bar notation over the 1
Step-by-step explanation: