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Nat2105 [25]
3 years ago
10

Can anyone help with this and explain...thanks so much!​

Mathematics
2 answers:
Oxana [17]3 years ago
5 0

Answer:

A" (-6, 3)

B" (-9, 0)

C" (-5, -1)

Step-by-Step explination:

You just add 4 to x then make it negative since it is reflecting over the y-axis(the vertical line). Then add 1 to y but it stays the same after that.

Sorry kind of bad at explaining but thats the best i can do for this problem, hoped it helped...

oksano4ka [1.4K]3 years ago
4 0

This is for reflection across the y-axis

A (-2,2)

B (-5,-1)

C (-1,-2)

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A grain silo has a circular base with an area of 260 square feet and is 21 feet tall What is the total volume?​
Leya [2.2K]

The correct answer is 5460 cubic feet or 5460 ft^{3}

Explanation:

The silo has a cylindrical shape, in this context, the volume of the silo or any other cylinder can be calculated by using the formula Volume =\pi r^{2} h. In this formula the symbol \pi refers to the number 3.1415..., the letter r refers to the radius of the base and the letter h refers to the height.

Moreover, in this case, it is known the heigh (21 feet) and the area of the base (260 square feet). Additionally, this area of the base is the result of the formula Area = \pi r^{2}, which is exactly the first section of the formula to find the volume. This implies that by multiplying the area of the base by the height the volume is known. Here is the process:

Volume = \pi r^{2} h  or  Volume = Ah   (Area of the base × height)

V = 260 square feet × 21 feet

V = 5460 cubic feet

6 0
2 years ago
Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me​
o-na [289]

Answer:

\frac{3}{2}

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

                   = - cos60cosx - sin60sinx

                   = - \frac{1}{2} cosx - \frac{\sqrt{3} }{2} sinx

squaring to obtain cos² (120 + x)

= \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

                   = -cos60cosx + sin60sinx

                   = - \frac{1}{2}cosx + \frac{\sqrt{3} }{2}sinx

squaring to obtain cos²(120 - x)

= \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x + \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

= cos²x + \frac{1}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}(cos²x + sin²x) = \frac{3}{2}

                 

5 0
2 years ago
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