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Mazyrski [523]
3 years ago
13

PLEASE HELP QUICK I NEED THIS

Mathematics
1 answer:
Delicious77 [7]3 years ago
6 0
The equation is y = -1/5x + 1
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Jack drove to work in the morning at an average speed of 45 miles per hour. He returned home in the evening along the same route
Dmitry [639]

Answer:

Step-by-step explanation:

Let's say that the time it took him to get to work in the morning is  t hours. Then the time it took him to get home in the afternoon must be 1 - t hours. We know that for any trip, distance equals rate times time or d = rt . That means that the distance he drove to work is given by , but we also know that the distance he drove to get home must be the same distance, because he took the same route (and, presumably, no one picked up him house and moved it while he was at work) so for the trip home we can say  d = 30 × (1 - t) and since the distances are equal, we can say: 

45t = 30 × (1 - t)

45t = 30 - 30t

45t + 30t = 30

75t = 30

t = 30/75

t = 2 /5 hour to drive to work at 45mph

Since ,  d = rt

d = 45 ×(2/5) = 18miles

8 0
3 years ago
If a scale drawing of a car is 3 inches and the real car is 15 feet what is the scale and the scale factor
mote1985 [20]

Answer:

5

Step-by-step explanation: 3x5=15

6 0
3 years ago
2(3x - 1) + 2(4x + 5) = 8
tigry1 [53]

Answer:

x=0

Step-by-step explanation:

2(3x - 1) + 2(4x + 5) = 8

Distribute

6x -2 +8x +10 =8

Combine like terms

14x +8 = 8

Subtract 8 from each side

14x+8-8=8-8

14x =0

Divide each side by 14

14x/14 = 0/14

x=0

3 0
3 years ago
Read 2 more answers
Ashley stacking two boxes on the shelf the bottom box measures 6 inches times 12 inches of the top box is a Q with one edge meas
Lerok [7]
76

6x12=72 and72+4=76 soo 76 is your awnser

4 0
3 years ago
Shown below is the solution to the linear program for finding Player A's optimal mixed strategy in a two-person, zero-sum game.
Luba_88 [7]

Answer:

Following are the answer to this question:

Step-by-step explanation:

For Option a:

Its optimal mixed approach for Player A's to Player A  

A1 with a chance of .05 utilizing technique  

Using the .60 chance strategy for A2  

Use the .35 possibility strategy for A3  

For Option b:

Optimal level mixed approach for team B:  

Use the strategy for B1 with a probability of 50  

Using the chance strategy for B2 at .50  

no  use strategy for B3  

For Option c:

The estimated gain of Player A will be= 3.500

For Option d:

The estimated loss of Player B will be 3.500

8 0
3 years ago
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