Answer:
answer is a . x²-8x+16=32
x²-8x=32-16
Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s
the only force acting on the object, is gravity, using feet will then be -32ft/s²,
was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues
so, we'll do the integral to get v(t) then

when will it reach the ground level? let's set s(t) = 0

part B) check the picture below
Answer:
4.
Step-by-step explanation:
(sec α - tan α)(sec α + tan α) = sec^2 α - tan^2α
But sec^2 α = 1 + tan^2 α so
sec^2 α - tan^2α = 1 + tan^2 α - tan^2α
= 1
so 1 = (sec α - tan α)(sec α + tan α) = 1/4 * x where x is sec α + tan α
1/4 * x = 1
x = 4.
Answer:
the answer C
Step-by-step explanation:
Answer:
y=2/7x
Step-by-step explanation:
y=mx+b where m=slope and b=y-intercept,
y=2/7x+0
y=2/7x