Answer:
Let x = the charge in 1st city before taxes
Let y = the charge in 2nd city before taxes
Set up equation before taxes.
y = x - 1500 eq1
Set up equation for total tax paid.
0.065x + 0.06y = 378.75 eq2
Substitute eq1 into eq2.
0.065x + 0.06(x - 1500) = 378.75
0.065x + 0.06x - 90 = 378.75
0.125x - 90 = 378.75
0.125x = 468.75
x = 3750
Substitute this value of x into eq1.
y = 3750 - 1500
y = 2250
The hotel charge in city one is $3750 and the hotel charge in city two is $2250
Answer:
StartFraction 6 Over 5 x Superscript 10 Baseline EndFraction
Step-by-step explanation:
Apparently you want to simplify ...

The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
1/a^b = a^-b
(a^b)^c = a^(bc)
__
So the expression simplifies as ...

To solve for the longest side, the hypotenuse, you have to use the pythagorean theorem. It will be 10^2 + 9^2 = c^2. 100 + 81 =c^2.
c^2 = 181 so c = sqrt(181).
to find sin of A do opposite/hypotenuse which gives you 9/sqrt(181)
to find cos of A do adjacent/hypotenuse which gives you 10/sqrt(181)
Answer:
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
because i know