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stiv31 [10]
3 years ago
11

Negative angles are measured in which direction from standard position?

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
4 0

Answer:

Clockwise

Step-by-step explanation:

The angle is measured from the initial side to the terminal side by the amount of rotation. The measurement is positive if measured in a counterclockwise direction. The measurement is negative if measured in a clockwise direction.

Bas_tet [7]3 years ago
3 0
The answer is clockwise
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Find the unknown angle measure by solving for the given variable
tiny-mole [99]

A straight line is 180°. So you can do:

(15x - 4) + (5x - 8) = 180  Simplify

20x - 12 = 180

20x = 192    Find the value of x

x = 9.6

m∠ABD = 15x - 4      Plug in x = 9.6

m∠ABD = 15(9.6) - 4 = 144 - 4 = 140°

m∠DBC = 5x - 8   Plug in 9.6

m∠DBC = 5(9.6) - 8 = 48 - 8 = 40°

3 0
3 years ago
) Supriya makes papadums to sell in her food truck. She uses 12 oz of dough to make each batch.
Anna11 [10]

The number of batches she can make is = 5 batches

<h3>Calculation of total number of batches</h3>

The amount of dough used to make each batch = 12oz

The total amount of dough she has= 60oz

Therefore, the number of batches she can make from the total dough available = b

Using the equation:

(dough for one batch) × (number of batches) = (total amount of dough)

which is = 12× b = 60

b= 60/12

b= 5 batches

Learn more about batches here:

brainly.com/question/25770607

4 0
2 years ago
The slope point equation of a line passing through the points (-3, -1) and (2, -6) is:
evablogger [386]

Answer:

y = -1x -4

Step-by-step explanation:

The point slope equation is y - y1 = m(x -x1).

You will have to plug in the points (-3, -1) and (2, -6).

y - (-1) = m (x - (-3))

To find "m", find y over x.

m = (y2 - y1) / ( x2 - x1)

m = (-6 + 1)/(2 + 3)

m = -5/5

m = -1

Then plug in "m"

y + 1 = -1(x + 3)

then distribute the "m" into the parenthesis and isolate y or subtract 1 from both sides.

y + 1 = -1x - 3

y = -1x -4

4 0
3 years ago
Use the intersect method to solve the equation. 14x^3-53x^2+41x-4=-4x^3-x^2+1x+4
UNO [17]

Answer:

x = (68 2^(1/3) + (27 i sqrt(591) + 445)^(2/3))/(27 (1/2 (27 i sqrt(591) + 445))^(1/3)) + 26/27 or x = (68 (-2)^(2/3) - (-2)^(1/3) (27 i sqrt(591) + 445)^(2/3))/(27 (27 i sqrt(591) + 445)^(1/3)) + 26/27 or x = 1/27 ((-2)/(27 i sqrt(591) + 445))^(1/3) ((-1)^(1/3) (27 i sqrt(591) + 445)^(2/3) - 68 2^(1/3)) + 26/27

Step-by-step explanation:

Solve for x over the real numbers:

14 x^3 - 53 x^2 + 41 x - 4 = -4 x^3 - x^2 + x + 4

Subtract -4 x^3 - x^2 + x + 4 from both sides:

18 x^3 - 52 x^2 + 40 x - 8 = 0

Factor constant terms from the left hand side:

2 (9 x^3 - 26 x^2 + 20 x - 4) = 0

Divide both sides by 2:

9 x^3 - 26 x^2 + 20 x - 4 = 0

Eliminate the quadratic term by substituting y = x - 26/27:

-4 + 20 (y + 26/27) - 26 (y + 26/27)^2 + 9 (y + 26/27)^3 = 0

Expand out terms of the left hand side:

9 y^3 - (136 y)/27 - 1780/2187 = 0

Divide both sides by 9:

y^3 - (136 y)/243 - 1780/19683 = 0

Change coordinates by substituting y = z + λ/z, where λ is a constant value that will be determined later:

-1780/19683 - 136/243 (z + λ/z) + (z + λ/z)^3 = 0

Multiply both sides by z^3 and collect in terms of z:

z^6 + z^4 (3 λ - 136/243) - (1780 z^3)/19683 + z^2 (3 λ^2 - (136 λ)/243) + λ^3 = 0

Substitute λ = 136/729 and then u = z^3, yielding a quadratic equation in the variable u:

u^2 - (1780 u)/19683 + 2515456/387420489 = 0

Find the positive solution to the quadratic equation:

u = (2 (445 + 27 i sqrt(591)))/19683

Substitute back for u = z^3:

z^3 = (2 (445 + 27 i sqrt(591)))/19683

Taking cube roots gives 1/27 2^(1/3) (445 + 27 i sqrt(591))^(1/3) times the third roots of unity:

z = 1/27 2^(1/3) (445 + 27 i sqrt(591))^(1/3) or z = -1/27 (-2)^(1/3) (445 + 27 i sqrt(591))^(1/3) or z = 1/27 (-1)^(2/3) 2^(1/3) (445 + 27 i sqrt(591))^(1/3)

Substitute each value of z into y = z + 136/(729 z):

y = (68 2^(2/3))/(27 (27 i sqrt(591) + 445)^(1/3)) + 1/27 (2 (27 i sqrt(591) + 445))^(1/3) or y = (68 (-2)^(2/3))/(27 (27 i sqrt(591) + 445)^(1/3)) - 1/27 (-2)^(1/3) (27 i sqrt(591) + 445)^(1/3) or y = 1/27 (-1)^(2/3) (2 (27 i sqrt(591) + 445))^(1/3) - (68 (-1)^(1/3) 2^(2/3))/(27 (27 i sqrt(591) + 445)^(1/3))

Bring each solution to a common denominator and simplify:

y = (2^(1/3) ((27 i sqrt(591) + 445)^(2/3) + 68 2^(1/3)))/(27 (445 + 27 i sqrt(591))^(1/3)) or y = (68 (-2)^(2/3) - (-2)^(1/3) (27 i sqrt(591) + 445)^(2/3))/(27 (445 + 27 i sqrt(591))^(1/3)) or y = 1/27 2^(1/3) (-1/(445 + 27 i sqrt(591)))^(1/3) ((-1)^(1/3) (27 i sqrt(591) + 445)^(2/3) - 68 2^(1/3))

Substitute back for x = y + 26/27:

Answer:  x = (68 2^(1/3) + (27 i sqrt(591) + 445)^(2/3))/(27 (1/2 (27 i sqrt(591) + 445))^(1/3)) + 26/27 or x = (68 (-2)^(2/3) - (-2)^(1/3) (27 i sqrt(591) + 445)^(2/3))/(27 (27 i sqrt(591) + 445)^(1/3)) + 26/27 or x = 1/27 ((-2)/(27 i sqrt(591) + 445))^(1/3) ((-1)^(1/3) (27 i sqrt(591) + 445)^(2/3) - 68 2^(1/3)) + 26/27

5 0
3 years ago
If a dart was thrown randomly at the dart board shown below, what is the probability that it would land between the outer circle
Mademuasel [1]

Answer:  B) 67%

<u>Step-by-step explanation:</u>

Find the Area of the Bullseye and Middle ring

A = π r²

A (inside) = π(8)² = 64π

Find the Area of the entire Target

A (target) = π (14)² = 196π

Find the Area of the Outer ring

A (outer ring) = A (target) - A(inside)

                      =   196 π    -    64π

                      =    132 π

The last step is to find the probability of landing on the outer ring:

P=\dfrac{success (area\ of\ outer\ ring)}{total\ possible\ outcomes(area\ of\ target)}=\dfrac{132\pi}{196\pi}=0.673=\large\boxed{67\%}

7 0
3 years ago
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