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Answer:
The first quartile of the strengths of this alloy is 9.055 GPa.
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The strength of an aluminum alloy is normally distributed with mean 10 gigapascals (GPa) and standard deviation 1.4 GPa.
This means that
What is the first [lower] quartile of the strengths of this alloy?
This is the 100/4 = 25th percentile, which is X when Z has a pvalue of 0.25, so X when Z = -0.675.
The first quartile of the strengths of this alloy is 9.055 GPa.
Using the t-distribution, the 96% confidence interval is given as follows:
(18.96, 21.04).
<h3>What is a t-distribution confidence interval?</h3>The confidence interval is:
In which:
is the sample mean.
- t is the critical value.
- n is the sample size.
- s is the standard deviation for the sample.
The critical value, using a t-distribution calculator, for a two-tailed 96% confidence interval, with 100 - 1 = 99 df, is t = 2.0812.
The parameters are given as follows:
Hence the bounds of the interval are:
More can be learned about the t-distribution at brainly.com/question/16162795
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