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3 years ago

What does the power source in a circuit provide?

Physics

1 answer:

Serjik [45]3 years ago

7 0

Explanation:

The primary function of a power supply is to convert electric current from a source to the correct voltage, current, and frequency to power the load. As a result, power supplies are sometimes referred to as electric power converters. Some power supplies are separate standalone pieces of equipment, while others are built into the load appliances that they power. Examples of the latter include power supplies found in desktop computers and consumer electronics devices. Other functions that power supplies may perform include limiting the current drawn by the load to safe levels, shutting off the current in the event of an electrical fault, power conditioning to prevent electronic noise or voltage surges on the input from reaching the load, power-factor correction, and storing energy so it can continue to power the load in the event of a temporary interruption in the source power (uninterruptible power supply).

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A car traveling at 40 ft/sec decelerates at a constant 5 feet per second per second. how many feet does the car travel before co

Tema [17]

<span>This problem is solved by the equation of motion: x = x0 + v0*t + 1/2*a*t^2, Here x0 = 0, v0 = 40ft/sec and a = -5 ft/s^2, we need to solve for t: v = v0 + a*t, solve how long does it take to stop: 0 = v0 + a*t --> a*t = -v0 --> t = -v0/a -- > 40/5 = 8 seconds to stop. In this time, the car travels x = 0 + 40*8 + 0.5*-5*8^2 ft ~ 160 ft. Answer: The car travels 160 ft.</span>

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3 years ago

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Crazy boy [7]

Where are the questions so that I can deliver a more accurate answer.

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3 years ago

NASA launches a satellite into orbit at a height above the surface of the Earth equal to the Earth's mean radius. The mass of th

Rzqust [24]

Answer:

a) 3h 59’ b) 5,590 m/s c) 1,910 N

Explanation:

The only force acting on the satellite (neglecting the influence of any other body) is just the attractive force from Earth, which is given by the Universal Law of Gravitation:

Fg = G* ms*me / (res² (1)

where: G = 6.67* 10⁻¹¹ N.m² / kg² ms = 780 kg, me= 5.97* 10²⁴ kg, and

res = 2* 6.38* 10⁶ m (distance between the center of the Earth and the satellite).

Fg = 1,910 N (answer c)

At the same time, this force, is the centripetal force that keeps the satellite in orbit, and that can be written as follows:

Fg = ms * v² / res (2)

By definition of velocity, we can say that the constant speed at which the satellite orbits, can be expressed as the quotient between the distance travelled around the Earth once, and the time needed to do that, which is called the period of the orbit:

v = 2*π*res / T (3)

We can solve for v first, taking the right sides of (1) and (2), as follows:

G* ms*me / (res)²= ms * v² / res

v = √(G*me/r) = 5,590 m/s (answer b)

Once obtained the value of v, we can replace in (3), and solve for T:

T = 2* π*res / v = 3 h 59 min (answer a)

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3 years ago

Desde un rascacielos de 300 m de altura se lanza un objeto con una velocidad inicial de 50 m/s. Calcula el tiempo que transcurre

rusak2 [61]

Answer:

a) t = 14.2 s , v = -92 m / s , b) v = - 59.16 m / s , t = 0.916 s

c) t = 7.75 s , x = 387.5 m

d) t = 10.64 s , x = 463.9 m , v = 92.2 m / s

Explanation:

This is an exercise in kinematics, suppose we take the upward direction as positive

a) is thrown up vertically.

Let's use the equation

y = y₀ + v₀ t - ½ g t²

When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²

0 = y₀ + v₀t - ½ g t²

½ 10 t² - 50 t - 300 = 0

Let's solve the quadratic equation

t² - 10 t - 60 = 0

t = [10 ±√ (10² + 4 60)] / 2

t = [10 ± 18.4] / 2

t₁ = 14.2 s

t₂ = -4.2 s

since time must be a positive quantity, the correctors result t = 14.2 s

the speed at this point is

v = v₀ - g t

v = 50 - 10 14.2

v = -92 m / s

the sign indicates that the body is going down

b) in this case the initial velocity is vo = -50 m / s

let's calculate the velocity on the ground

v² = v₀² - 2g (y-y₀)

v² = 50 2 - 2 10 ((0- 300)

v² = 3500

v = + - 59.16 m / s

as the body is going down the correct sign is the negative

v = - 59.16 m / s

the time it takes to arrive is

v = v₀ - g t

t = (v₀ - v) / g

t = (-50 + 59.16) / 10

t = 0.916 s

c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0

y = y₀ + v₀ t - ½ g t²

0 = 300 + 0 - ½ 10 t²

t = √ (2 300/10)

t = 7.75 s

the horizontal displacement at this time is

x = v₀ₓ t

x = 50 7.75

x = 387.5 m

d) as it is thrown with an angle let's find each component of the velocities

v₀ₓ = v₀ cos 30

$v_{oy}$ = v₀ sin 30

v₀ₓ = 50 cos 30 = 43.3 m / s

v_{oy} = 50 sin 30 = 25 m / s

we look for the time of descent

y = y₀ + v_{oy} t - ½ g t²

0 = y₀ + v_{oy} t - ½ g t²

0 = 300 + 25 t - ½ 10 t²

t² - 5t - 60 = 0

we solve the second degree equation

t = [5 ±√ (5² + 4 60)] / 2

t = [5 ± 16.28] / 2

t₁ = 10.64 s

t₂ = -5.64 s

since the time must be positive the result is t = 10.64 s

the range on the x axis is

x = v₀ₓ t

x = 43.6 10.64

x = 463.9 m

the ground speed is

v_{y} = $v_{oy}$ - g t

v_{y} = 25 - 10 10.64

v_{y} = -81.4 m / s

speed is

v = √ (v₀ₓ² + v_{y}²)

v = √ (43.3² + 81.4²)

v = 92.2 m / s

7 0

3 years ago

C. 5 mi., North is it a scalar or vector<br>

Hunter-Best [27]

Answer:

Vector.

Explanation:

A vector has both magnitude and direction.

A scalar has just magnitude.

4 0

3 years ago