A box sits at the top of an incline that is 50.0 cm tall and that makes an angle of 25° with the ground. The box has a mass of
1 answer:
As the box sits at the top of an incline that is 50.0 cm tall and makes an angle of 25° with the ground, The time it takes to reach the bottom of the incline is mathematically given as
t=0.148s
<h3>What is the time it takes the box to reach the bottom of the incline?</h3>Generally, the equation for the acceleration is mathematically given as
Therefore
a=(9.8sin-(0.15cos35))
a=4.417
Thereofore
v^2=v0^2+2al
v=2.6533
In conclusion, The time t is
t=v-v0/a
2.65-20/4.417
t=0.148s
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Answer:
245.45km in a direction 21.45° west of north from city A
Explanation:
Let's place the origin of a coordinate system at city A.
The final position of the airplane is given by:
rf = ra + rb + rc where ra, rb and rc are the vectors of the relative displacements the airplane has made. If we separate this equation into its x and y coordinates:
rfX = raX+ rbX + rcX = 175*cos(30)-150*sin(20)-190 = -89.75km
rfY = raY + rbY + rcT = 175*sin(30)+150*cos(20) = 228.45km
The module of this position is:
And the angle measure from the y-axis is:
So the answer is 245.45km in a direction 21.45° west of north from city A