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Colt1911 [192]
2 years ago
15

A box sits at the top of an incline that is 50.0 cm tall and that makes an angle of 25° with the ground. The box has a mass of

2.0 kg. It is given an initial speed of 3.0 m/s down the incline. If the coefficient of kinetic friction between the box and the incline is 0.10, how long does it take the box to reach the bottom of the incline?
Physics
1 answer:
DiKsa [7]2 years ago
7 0

As the box sits at the top of an incline that is 50.0 cm tall and makes an angle of 25° with the ground, The time it takes to reach the bottom of the incline is mathematically given as

t=0.148s

<h3>What is the time it takes the box to reach the bottom of the incline?</h3>

Generally, the equation for the acceleration  is mathematically given as

a=g(sin\theta-uscos\theta)

Therefore

a=(9.8sin-(0.15cos35))

a=4.417

Thereofore

v^2=v0^2+2al

v^2=V0^2+2ahsin\theta\\\\V^2=(2.0+2(4.417))*60*0.01sin35

v=2.6533

In conclusion, The time t is

t=v-v0/a

2.65-20/4.417

t=0.148s

Read more about  Arithmetic

brainly.com/question/22568180

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Answer:

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Solving for C, we find:

C=\frac{E}{\Delta T}=\frac{3276}{8.8}=372.3 J/^{\circ}C

5 0
3 years ago
The speed v of a sound wave traveling in a medium that has bulk modulus b and mass density ρ (mass divided by the volume) is v=b
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As it is given that Bulk modulus  and density related to velocity of sound

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<h3>What is water runoffs?</h3>

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<h3>What is precipitation?</h3>

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5 0
2 years ago
1. Two forces F~ 1 and F~ 2 are acting on a block of mass m=1.5 kg. The magnitude of force F~ 1 is 12N and it makes an angle of
VLD [36.1K]

Answer:

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6 0
3 years ago
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