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Afina-wow [57]
3 years ago
8

9c-6c-2c+5c=18 solve for c

Mathematics
2 answers:
Yuri [45]3 years ago
4 0
C=3

9c minus 6c is 3c
3c minus 2c is 1c or c
c plus 5c is 6c

18 divided by 6 is 3
AveGali [126]3 years ago
3 0

Answer: c = 3

Step-by-step explanation: First, make sure you simplify the left side of the equation by combining our <em>c terms</em> together.

So we have 9c - 6c - 2c + 5c which simplifies to 6c.

So now we have the equation 6c = 18.

To solve for <em>c</em> in this equation, we want to get <em>c</em> by itself on the left side of the equation. Since <em>c</em> is being multiplied by 6, to get <em>c</em> by itself, we need to divide by 6 on the left side of the equation. Since we divided by 6 on the left side, we must also divide by 6 on the right side.

On the left side, the 6's cancel out so we're simply left with <em>c</em>. On the right side we have 18 divided by 6 which is 3 so we have <em>c = 3</em>.

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Answer:

B

Step-by-step explanation:

(c - 2d) (3c - 2d) =  c*(3c -2d) - 2d(3c - 2d)

6 0
3 years ago
How to you solve 7 7/10- 3 4/5
Vera_Pavlovna [14]
Make them both improper fractions.
77/10 - 19/5

Give them common denominators (multiply the second fraction by 2)
77/10 - 38/10

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8 0
3 years ago
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WILL GIVE BRAINLIEST!!
VMariaS [17]

Answer:

A(-1,4)\to A''(-1,-1)

B(0,2)\to B''(1,0)

C(1,2)\to C''(1,1)

D(-2,4)\to D''(-1,2)

Step-by-step explanation:

The given trapezoid has vertices at A(−1,4), B(0,2), C(1,2) and D(2,4).

The transformation rule for 90° counterclockwise rotation is

(x,y)\to(-y,x)

This implies that:

A(-1,4)\to A'(-4,-1)

B(0,2)\to B'(-2,0)

C(1,2)\to C'(-2,1)

D(2,4)\to D'(-4,2)

This is followed by a translation 3 units to the right.

This also has the rule: (x,y)\to (x+3,y)

A'(-4,-1)\to A''(-1,-1)

B'(-2,0)\to B''(1,0)

C'(-2,1)\to C''(1,1)

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Therefore:

A(-1,4)\to A''(-1,-1)

B(0,2)\to B''(1,0)

C(1,2)\to C''(1,1)

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3 0
3 years ago
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artcher [175]
6 units to the right
5 0
3 years ago
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givi [52]

Answer:

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Step-by-step explanation:

1)

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  • Rate of increase = 10%

<u>Number of students after 6 years:</u>

  • a_6 = 2988(1+0.1)^{6-1} = 4812

2)

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<u>Amount of gold after 4 years:</u>

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b)

<u>Salary in the 5th year:</u>

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