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2 years ago

Hola espero que tengan un buen día, me ayudan con mi tarea por favor? =)

Mathematics

1 answer:

ValentinkaMS [17]2 years ago

3 0

Answer:

ella uso 1202403.6 chispas de chocolate para cada charola de panques

oh algo asi no se jajjaja

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Help ill give you Brainliesttt ‼️‼️‼️‼️‼️‼️

Lesechka [4]

Answer:

Step-by-step explanation:

+ we take t- number of tickets and each ticket cost $7.

So t is too the number of people who buy tickets, then

$0\leq t\leq 200$

A) We can calculate the amount of money: M= 7t where $0\leq t\leq 200$

B) The domain for t is $0\leq t\leq 200$ , t is an integer.

C) The range for the amount M:

$0*7\leq M\leq 200*7\\0\leq M\leq 1400$

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2 years ago

Devon writes a number pattern. He starts with 3 and follows the rule “multiply by

Fed [463]

Answer:

3,6,12,24.48,96,192

Step-by-step explanation:

3 0

2 years ago

Add 1/ 10 11/100 and select the correct answer. all i got is 12/100 pleaseee help i tried

Vesnalui [34]

I think it's 21/100 because I found the common denominator by multiplying by ten so I multiplied 1 times ten to get 10. Does that help?

3 0

3 years ago

Which polynomial correctly combines the like terms and puts the given polynomial in standard form? -5x^3y^3+8x^4y^2-xy^5-2x^2y^4

victus00 [196]

Given:

The polynomial is:

$-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5$

To find:

The simplified form of the given polynomial in standard form.

Solution:

We have,

$-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5$

Combining the like terms, we get

$=-5x^3y^3+8x^4y^2+(-2x^2y^4+3x^2y^4)+8x^6+(-xy^5-6xy^5)$

$=-5x^3y^3+8x^4y^2+x^2y^4+8x^6-7xy^5$

Now, rewrite this polynomial in standard form.

$=8x^6+8x^4y^2-5x^3y^3+x^2y^4-7xy^5$

Therefore, the required polynomial in standard form is $8x^6+8x^4y^2-5x^3y^3+x^2y^4-7xy^5$ .

8 0

2 years ago

The equation of a circle whose center is at ( 4,0 ) and radius is length 2 ( square root ) 3

Vesna [10]

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the center
r - the radius

The center is (4,0), the length of the radius is 2√3.
$(x-4)^2+(y-0)^2=(2\sqrt{3})^2 \\
\boxed{(x-4)^2+y^2=12}$

8 0

2 years ago

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