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vekshin1
3 years ago
12

This is for middle school 9th grade please help me :)

Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0

Answer:

i think it's undefined

Step-by-step explanation:

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3 years ago
what is the quotient (65y3 15y2 − 25y) ÷ 5y? a. 13y2 3y − 5 b. 13y3 3y2 − 5y c. 13y2 − 3y 5 d.13y2 − 3y − 5
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Keywords:

<em>Division, quotient, polynomial, monomial </em>

For this case we must solve a division between a polynomial and a monomial and indicate which is the quotient.

By definition, if we have a division of the form: \frac {a} {b} = c, the quotient is given by "c".

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C (y) represents the quotient of the division:

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C (y) = \frac {65y ^ 3} {5y} + \frac {15y ^ 2} {5y} - \frac {25y} {5y}

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Thus, the quotient of the division between the polynomial and the monomial is given by:

C (y) = 13y ^ 2 + 3y-5

Answer:

The quotient is: C (y) = 13y ^ 2 + 3y-5

Option: A


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\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}&#10;\\\\\\&#10;therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}&#10;\\\\&#10;-------------------------------\\\\&#10;sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13}  \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}
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3 years ago
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