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Usimov [2.4K]
3 years ago
10

What is the slope of the line between (3, -4) and (-2, 1)?

Mathematics
1 answer:
k0ka [10]3 years ago
5 0
M=<u>(y2-y1)</u>
     (x2-x1) m= rise over run. That is the correct formula to find your slope.
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The cos of 16 degrees is 0.96
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Please help as soon as possible Will mark BRAINLIEST!!!!!
omeli [17]

Answer:

Width = 40ft

Step-by-step explanation:

Area of a rectangle = Length x Width

=> 1600 = 40 x W

=> 1600 = 40W

=> 1600/40 = 40W/40

=> 40 = W

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Which pairs of quadrilaterals can be shown to be congruent using rigid motions?
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Answer:

1 and 2 are not congruent; 1 and 3 are congruent; 1 and 4 are congruent; 2 and 3 are not congruent; 2 and 4 are not congruent; 3 and 4 are congruent.

Step-by-step explanation:

From the diagram, we can see that the angle measures and side measures of figures 1, 3 and 4 are the same.  This means that these three figures are congruent.  Figure 2, however, is not congruent to any of the other 3.

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3 years ago
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Triangle ABC is an isosceles triangle. Angles B and C are base angles, with measurements of (11x −10)° and (7x + 10)°, respectiv
Ulleksa [173]

Answer:

m∠A = 90°

Step-by-step explanation:

In isosceles triangle base angles are congruent. That means we can equate measurments of angle B and angle C and solve for x!

m∠B = m∠C

11x - 10 = 7x + 10

4x - 10 = 10

4x = 20

x = 5

Now let's insert x back in the expressions for angles.

m∠B = (11x − 10)° = (11(5) − 10)° = 45°

m∠C = (7x + 10)° = (7(5) + 10)° = 45°

<u>Sum of all angles in the triangle is 180°.</u> Let's make an equation.

m∠A + m∠B + m∠C = 180°

m∠A + 45°+ 45° = 180°

m∠A  = 90°

7 0
1 year ago
2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
3 years ago
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