Answer:




![(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18](https://tex.z-dn.net/?f=%282%20%2A%20%5Csqrt%7B16%7D%29%20-%20%28%5Csqrt%5B3%5D%7B27%7D%20%2A%20%5Csqrt%7B81%7D%29%20%2B%201%20%3D%20-18)
Step-by-step explanation:
<em>Required: Solve the expressions using proper operation order</em>
To solve this, we'll make use of BODMAS
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Evaluate all squares and square roots


Evaluate the numerator (Start by multiplying 3 * 3)

Subtract 9 from 41

Evaluate the denominator (Start by multiplying 6 * 3)


Divide 32 by -8
-4
Hence;

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Start by evaluating the bracket

Then evaluate the multiplication

Simplify the square root

Split the square root

Take Square root of 4


Hence;

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Evaluate 7²

Evaluate all expression in the bracket


Evaluate 3 * 5



Hence;

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Evaluate 7²

Evaluate 5 * 8



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![(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1](https://tex.z-dn.net/?f=%282%20%2A%20%5Csqrt%7B16%7D%29%20-%20%28%5Csqrt%5B3%5D%7B27%7D%20%2A%20%5Csqrt%7B81%7D%29%20%2B%201)
Evaluate all square root and cube root

Solve the expressions in bracket


Hence;
![(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18](https://tex.z-dn.net/?f=%282%20%2A%20%5Csqrt%7B16%7D%29%20-%20%28%5Csqrt%5B3%5D%7B27%7D%20%2A%20%5Csqrt%7B81%7D%29%20%2B%201%20%3D%20-18)
Answer:

Step-by-step explanation:

Answer:
0.5(_12m_) - 0.5(_22n_)
Step-by-step explanation:
To apply the distributive property multiply each the term outside to each term in the parenthesis.
0.5(12m - 22n) 0.5(12m - 22n =0.5(_12m_) - 0.5(_22n_)
Answer:
15.0
Step-by-step explanation:
Square root entire equation (-8 - 7)^2 + (-5 + 4)^2
Answer:
C
Step-by-step explanation:
To make it easy let's start by organizing our information :
- AC=12 AND BD=8
- ABCD is a rhombus
- K and L are the midpoints of sides AD and CD
- we notice that the rhombus ABCD is divided into four right triangles
What do you think of when you hear a right triangle ?
- The pythagorian theorem !
AC and BD are khown so let's focus on them .
If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?
Simply because they are the diagonals of a rhombus .
ow let's apply the pythagorian theorem :
- (AC/2)² + (BD/2)² = BC²
- 6²+4²=52
- BC²= 52⇒
=BC
Now we khow that : AB=BC=CD=AD=
This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle
- KL is parallel to AC
- k is the midpoint of AD and L of DC
I smell something . yes! Thales theorem
- KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
- KL/12=
/2*
- KL/12=1/2⇒ KL=6
Now we have the length of the base kl
Now the big boss the height :
- notice that you khow the length of KL
- BD crosses kl from its midpoint and DL =
/2
What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D
- DL²=(KL/2)²+D²
- 52/4= 9+ D²
- D² = 52/4-9 +4 SO D=2
now the height of the trigle is H= BD-D= 8-2=6
NOw the area of the triangle is :
- A=(KL*H)/2 ⇒ A= (6*6)/2=18
THE ANSWER IS 18 SQ.UN