I'm pretty sure the answer is D
Answer:
x=3
Step-by-step explanation:
subtract 2x from both sides then you are left with 3=4x-9
add 9 to both sides then you have 12=4x then divide both sides by 4 and x=3
Answer:
option D
Step-by-step explanation:
x=-1 and x=-3 are the real zeros
We plug in the x values in each equation and check which equation makes y=0
A) y=x^4-4x^3-4x^2-4x-3
x=-1 , ![y=(-1)^4-4(-1)^3-4(-1)^2-4(-1)-3= 2](https://tex.z-dn.net/?f=y%3D%28-1%29%5E4-4%28-1%29%5E3-4%28-1%29%5E2-4%28-1%29-3%3D%202)
x=-3 , ![y=(-3)^4-4(-3)^3-4(-3)^2-4(-3)-3= 162](https://tex.z-dn.net/?f=y%3D%28-3%29%5E4-4%28-3%29%5E3-4%28-3%29%5E2-4%28-3%29-3%3D%20162)
y is not equal to 0 so option A is not correct
B.y=-x^4-4x^3+4x^2+4x+3
x=-1 , ![y=(-1)^4-4(-1)^3+4(-1)^2+4(-1)+3=6](https://tex.z-dn.net/?f=y%3D%28-1%29%5E4-4%28-1%29%5E3%2B4%28-1%29%5E2%2B4%28-1%29%2B3%3D6%20)
x=-3 , ![y=(-3)^4-4(-3)^3+4(-3)^2+4(-3)+3=54](https://tex.z-dn.net/?f=y%3D%28-3%29%5E4-4%28-3%29%5E3%2B4%28-3%29%5E2%2B4%28-3%29%2B3%3D54%20)
y is not equal to 0 so option B is not correct
C.y=x^4+4x^3+3x^2+4x-4
x=-1 , ![y=(-1)^4+4(-1)^3+4(-1)^2+4(-1)-4= -8](https://tex.z-dn.net/?f=y%3D%28-1%29%5E4%2B4%28-1%29%5E3%2B4%28-1%29%5E2%2B4%28-1%29-4%3D%20-8)
x=-3 , ![y=(-3)^4+4(-3)^3+4(-3)^2+4(-3)-4= -16](https://tex.z-dn.net/?f=y%3D%28-3%29%5E4%2B4%28-3%29%5E3%2B4%28-3%29%5E2%2B4%28-3%29-4%3D%20-16)
y is not equal to 0 so option C is not correct
D) y=x^4+4x^3+4x^2+4x+3
x=-1 , ![y=(-1)^4+4(-1)^3+4(-1)^2+4(-1)+3= 0](https://tex.z-dn.net/?f=y%3D%28-1%29%5E4%2B4%28-1%29%5E3%2B4%28-1%29%5E2%2B4%28-1%29%2B3%3D%200)
x=-3 , ![y=(-3)^4+4(-3)^3+4(-3)^2+4(-3)+3= 0](https://tex.z-dn.net/?f=y%3D%28-3%29%5E4%2B4%28-3%29%5E3%2B4%28-3%29%5E2%2B4%28-3%29%2B3%3D%200)
y=0 so option D has two real zeros x=-1 and x=-3
Step-by-step explanation:
The point-slope form of an equation of a line:
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
m - slope
(x₁, y₁) - given point
![\bullet\ (2,\ 7),\ m=-4\\\\y-7=-4(x-2)\\\\\bullet(-6,\ -2),\ m=3\\\\y-(-2)=3(x-(-6))\to y+2=3(x+6)\\\\\bullet(12,\ 5),\ m=-3\\\\y-5=-3(x-12)\\\\\bullet(7,\ -6),\ m=\dfrac{1}{2}\\\\y-(-6)=\dfrac{1}{2}(x-7)\to y+6=\dfrac{1}{2}(x-7)\\\\\bullet(4,\ -5),\ m=6\\\\y-(-5)=6(x-4)\to y=y+5=6(x-4)\\\\\bullet(-8,\ 2),\ m=-\dfrac{3}{4}\\\\y-2=-\dfrac{3}{4}(x-(-8))\to y-2=-\dfrac{3}{4}(x+8)](https://tex.z-dn.net/?f=%5Cbullet%5C%20%282%2C%5C%207%29%2C%5C%20m%3D-4%5C%5C%5C%5Cy-7%3D-4%28x-2%29%5C%5C%5C%5C%5Cbullet%28-6%2C%5C%20-2%29%2C%5C%20m%3D3%5C%5C%5C%5Cy-%28-2%29%3D3%28x-%28-6%29%29%5Cto%20y%2B2%3D3%28x%2B6%29%5C%5C%5C%5C%5Cbullet%2812%2C%5C%205%29%2C%5C%20m%3D-3%5C%5C%5C%5Cy-5%3D-3%28x-12%29%5C%5C%5C%5C%5Cbullet%287%2C%5C%20-6%29%2C%5C%20m%3D%5Cdfrac%7B1%7D%7B2%7D%5C%5C%5C%5Cy-%28-6%29%3D%5Cdfrac%7B1%7D%7B2%7D%28x-7%29%5Cto%20y%2B6%3D%5Cdfrac%7B1%7D%7B2%7D%28x-7%29%5C%5C%5C%5C%5Cbullet%284%2C%5C%20-5%29%2C%5C%20m%3D6%5C%5C%5C%5Cy-%28-5%29%3D6%28x-4%29%5Cto%20y%3Dy%2B5%3D6%28x-4%29%5C%5C%5C%5C%5Cbullet%28-8%2C%5C%202%29%2C%5C%20m%3D-%5Cdfrac%7B3%7D%7B4%7D%5C%5C%5C%5Cy-2%3D-%5Cdfrac%7B3%7D%7B4%7D%28x-%28-8%29%29%5Cto%20y-2%3D-%5Cdfrac%7B3%7D%7B4%7D%28x%2B8%29)