We have been given that in ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. We are asked to find the length of IJ to the nearest tenth of a foot.
First of all, we will draw a right triangle using our given information as shown in the attachment.
We can see that in triangle HIJ, the side IJ is adjacent side to angle I and JH is opposite side to angle I.
We know that tangent relates opposite side of right triangle to adjacent side.
Upon rounding to nearest tenth, we will get:
Therefore, the length of the side IJ is approximately 258.8 units.
12.0 is the answer I think
You don't need to understand the construction or why it works. You only need to accept the fact that it does. You can figure out the answers to this question by looking at the picture.
RT is tangent to circle Q -- TRUE. That is the point of the construction.
QT is a radius of circle Q -- TRUE. Q is the center and T is on the circle. A line segment from the center to a point on the circle is a radius.
m∠QSR = 90° -- FALSE. Those points lie on the same line. The measure of the angle is 180°.
QS = QT -- FALSE. S lies inside circle Q, so is closer to the center than T, which lies on the circle. (For some choice of point R, S might lie on the circle, but because this statement is not always true, it must be considered false.)
ΔRTQ is a right triangle -- TRUE. A tangent line is always perpendicular to the radius to the point of tangency. The construction succeeds because RTQ is inscribed in semicircle RTQ (centered at S). Such a triangle is always a right triangle.
Answer:
y is 70° and x is 40 °
Step-by-step explanation:
the triangle has two equal sides as shown on the diagram...so the next angle to 110° which is 70° is equal to y....then by calculation y + x should give us 110° so if y is 70 then x is 40.
Each team will paint 238 ft of the fence.
Step-by-step explanation:
Length of fence = 1666 ft
Number of students teams = 7
Let x be the length covered by each team, therefore,
7x=1666
Dividing both sides by 7;
Each team will paint 238 ft of the fence.
Keywords: length, division
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