Question

In ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. Find the length of IJ to the nearest tenth of a foot.

Answer 1

Answer:

it's 158.8

Step-by-step explanation:

Answer 2

We have been given that in ΔHIJ, the measure of ∠J=90°, the measure of ∠I=29°, and JH = 88 feet. We are asked to find the length of IJ to the nearest tenth of a foot.

First of all, we will draw a right triangle using our given information as shown in the attachment.  

We can see that in triangle HIJ, the side IJ is adjacent side to angle I and JH is opposite side to angle I.

We know that tangent relates opposite side of right triangle to adjacent side.

$\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}$

$\text{tan}(29^{\circ})=\frac{88}{IJ}$

$IJ=\frac{88}{\text{tan}(29^{\circ})}$

$IJ=\frac{88}{0.554309051453}$

$IJ=158.7562024638191237$

Upon rounding to nearest tenth, we will get:

$IJ\approx 158.8$

Therefore, the length of the side IJ is approximately 258.8 units.